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kykrilka [37]
3 years ago
10

A lamp draws a current of 0.1 A when it is connected to a 122-V source. (

Physics
1 answer:
Setler79 [48]3 years ago
4 0
The power of the lamp would be calculated with the equation of ohm laws. P = U x I = 122V x 0.1A = 12.2W
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A motorcycle passes over the top of a hill that has a radius of curvature of 100 m. The mass of the motorcycle plus rider is 300
lorasvet [3.4K]

Answer:

F_N>F_N'

Explanation:

From the question we are told that

Radius of curvaturer=100m

Mass M=300kg

initial Speed of Motorcycle  V_1=30m/s

Final  Speed of Motorcycle  V_2=33m/s

Generally the equation Force at initial speed is  mathematically given as

F_N=mg-\frac{mv^2}{R}

F_N=300*9.8-\frac{(300*30)^2}{100}

F_N=240N

Generally the equation Force at Final speed is  mathematically given as

F_N'=mg-\frac{mv'^2}{R}

F_N'=300*9.8-\frac{(300*33)^2}{100}

F_N'=-327N

Therefore

F_N>F_N'

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3 years ago
One kilogram of the explosive TNT supplies explosive energy of about 4.2×10^6 J. Let's see what that energy can achieve in lifti
makkiz [27]

Answer:

4,0000

Explanation:

3 0
3 years ago
Explain how a ship made of materials that are much denser than water is able to float on water?
Helen [10]
It is because the weight is equal to each other and balances out. example war ships have tons of metal, but it spreads the weight on the water
7 0
4 years ago
What is the meaning of s in heat energy?​
ValentinkaMS [17]

Answer:Specific heat is the amount of heat required to raise one gram of any substance one degree Celsius or Kelvin. The formula for specific heat is the amount of heat absorbed or released = mass x specific heat x change in temperature.

.

Explanation:

HOPE IT HELP

6 0
3 years ago
Suppose you are at the center of a large freely-rotating horizontal turntable in a carnival funhouse. As you crawl toward the ed
I am Lyosha [343]

Answer:

c. remains the same, but the RPMs decrease.

Explanation:

Because there aren't external torques on the system composed by the person and the turntable it follows that total angular momentum (I) is conserved, that means the total angular momentum is a constant:

\overrightarrow{L}=constant

The total angular momentum is the sum of the individual angular momenta, in our case we should sum the angular momentum of the turntable and the angular momentum of a point mass respect the center of the turntable (the person)

\overrightarrow{L_{turnatble}}+\overrightarrow{L_{person}}=constant (1)

The angular momentum of the turntable is:

\overrightarrow{L_{turnatble}}=I\overrightarrow{\omega} (2)

with I the moment of inertia and ω the angular velocity.

The angular momentum of the person respects the center of the turntable is:

\overrightarrow{L_{person}}=\overrightarrow{r}\times m\overrightarrow{v} (3)

with r the position of the person respects the center of the turntable, m the mass of the person and v the linear velocity

Using the fact v=\omega r:

\overrightarrow{L_{person}}=\overrightarrow{r}\times rm\overrightarrow{\omega}(3)

By (3) and (2) on (1) and working only the magnitudes (it's all that we need for this problem):

I\omega+r^{2}m\omega=constant

\omega(I+r^{2}m)=constant

Because the equality should be maintained, if we increase the distance between the person and the center of the turntable (r), the angular velocity should decrease to maintain the same constant value because I and m are constants, so the RPM's (unit of angular velocity) are going to decrease.

4 0
4 years ago
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