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Elenna [48]
4 years ago
7

Kiko writes a roport to compare and contrast the code of plants and animals. Which of the following statements is accurato arvd

bolony in Kiko's report?
The cell membrane of animals is much tickow than those in plants
Vaculos in plants are much larger than those in animals
Animal colls do not have chromosomos
Plant colls do not have chloroplasts
Physics
1 answer:
eduard4 years ago
8 0

Answer:

Kiko writes a roport to compare and contrast the code of plants and animals. Which of the following statements is accurato arvd bolony in Kiko's report?

The cell membrane of animals is much tickow than those in plants

Vaculos in plants are much larger than those in animals

Animal colls do not have chromosomos

Plant colls do not have chloroplasts

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An equipotential surface that surrounds a point charge q has a potential of 536 V and an area of 1.20 m2. Determine q.
gladu [14]

Answer:

q = 1.84×10^-8coulombs

Explanation:

Surface area = 4πr²

r is the distance

1.2 = 4(3.14)r²

1.2 = 12.56r²

r² = 1.2/12.56

r² = 0.0956

r = √0.0956

r = 0.309m

Get the charge C

V = kq/r

536 = 9.0×10^9q/0.309

536×0.309 = 9×10^9q

165.73 = 9×10^9q.

q = 165.73/9×10^9

q = 1.84×10^-8coulombs

4 0
3 years ago
A 4.15-volt battery is connected across a parallel-plate capacitor. Illuminating the plates with ultraviolet light causes electr
FromTheMoon [43]

Answer:

a ) 2.13 X 10⁶ m/s .

b ) 1.28 X 10⁶ m/s

Explanation:

When electrons are repelled by negative plates and attracted by positive plates , it will increase their kinetic energy.

Increase in their energy = 4.15 eV

= 4.5 X 1.6 X 10⁻¹⁹ J

= 6.64 x 10⁻¹⁹ J

Initial kinetic energy

= 1/2 mv²

= 1/2 x 9.1 x 10⁻³¹ x ( 1.76 x 10⁶)²

= 14.09 X 10⁻¹⁹ J

Total energy

= 6.64 x 10⁻¹⁹+14.09 X 10⁻¹⁹

= 20.73 x 10⁻¹⁹

If V be the increased velocity

1/2 m V² = 20.73 X 10⁻¹⁹

.5 X 9.1 X 10⁻³¹ V² = 20.73 X 10⁻¹⁹

V = 2.13 X 10⁶ m/s .

b ) When electrons are released from positive plate , their speed are reduced because of attraction between electrons and positively charge plates.

Initial kinetic energy

= 14.09 x 10⁻¹⁹ J (see above )

reduction in kinetic energy  

= 6.64 x 10⁻¹⁹ J ( See above )

Total energy with electron -

= 14.09 x 10⁻¹⁹  - 6.64 x 10⁻¹⁹

= 7. 45 x 10⁻¹⁹ J .

If V be the energy of electrons reaching the negative plate,

1/2 m V² =7. 45 x 10⁻¹⁹

V = 1.28 X 10⁶ ms⁻¹

6 0
4 years ago
How many milliliters of water would be displaced by 408 G of lead?
Oksana_A [137]

408 grams has a volume of 408/11.35= 35.947cc

It displaces 35.947cc of water then it =35.947 milliliters


(If this isn't the answer please let me know and I'll help you the best I can. I hope you have a great day and enjoy!)

7 0
3 years ago
Consider two points in an electric field. The potential at point 1, V1 is 31 V.The potential at point 2, V2 is 168 V. A proton i
hram777 [196]

Answer:

Explanation:

V1 = 31 V

V2 = 168 V

charge on proton, q = e

(a)

The change in potential energy is given by

ΔU = q ( V2 - V1)

ΔU = e (v2 - V1)

(b)

ΔU = e (168 - 31)

ΔU = 137 eV

(c)

Work done = change in potential energy

W = 137 eV

W = 137 x 1.6 x 10^-19

W = 2.19 x 10^-17 J

8 0
3 years ago
What will be the fundamental frequency and first three overtones for a 26cm long organ at 20°C if it is open ( at 20°C, the spee
kakasveta [241]

Explanation:

The frequency of an organ pipe if it is open is given by :

f=\dfrac{nv}{2l}

v is speed of sound in air is 343 m/s at 20°C

For fundamental frequency, n = 1

f=\dfrac{1\times 343}{2\times 0.26}\\\\f=659.61\ Hz

First overtone frequency,

f_1=2f\\\\f_1=2\times 659.61\\\\f_1=1319.22\ Hz

Second overtone frequency,

f_2=3f\\\\f_2=3\times 659.61\\\\f_2=1978.83\ Hz

Third overtone frequency

f_3=4f\\\\f_3=4\times 659.61\\\\f_3=2638.44\ Hz

Hence, this is the required solution.

3 0
3 years ago
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