Answer:
Acceleration = 2.35 m/
Speed = 8.67 m/s
Explanation:
The coefficient of friction , u =0.3
The angle of incline = 30°
The two forces acting on block are weight and friction.
weight along the incline = mg cos60° = 
= 0.5 mg
Friction along incline = umg cos30° = mg 
Friction along incline = 0.26 mg
Net force acting on the weight = (0.5 - 0.26) mg = 0.24 mg
Acceleration = 
= 0.24 g = 2.35 m/
The height of incline = 8 m
Length of the inclined edge = 16 m
v= 8.67 m/s
Answer:
a:it speed up
b:it should be positive since final
velocity is larger than initial velocity
c:acceleration is approximately 4.5
m/s^2
Explanation:
initial velocity=u=4.47m/s
Final velocity=v=17.9m/s
Time=t=3 seconds
a:the car speed up since the velocity
increased
b:change in velocity is positive
because final velocity is larger than
initial velocity
17.9-4.47=13.43 m/s
c: acceleration=(v-u)/t
acceleration=(17.9-4.47)/3
acceleration=13.43/3
acceleration=4.5 m/s^2
Answer:
42.5 m/s
Explanation:
Given:
x₀ = 0 m
x = 62 m
y₀ = 80 m
y = 0 m
v₀ᵧ = 0 m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
Find: v
First, find the time it takes to land.
y = y₀ + v₀ᵧ t + ½ aᵧ t²
(0 m) = (80 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 4.04 s
Find the horizontal component vₓ:
x = x₀ + vₓ t − ½ aₓ t²
(62 m) = (0 m) + vₓ (4.04 s) − ½ (0 m/s²) (4.04 s)²
vₓ = 15.3 m/s
Find the vertical component vᵧ:
vᵧ = aᵧ t + v₀ᵧ
vᵧ = (-9.8 m/s²) (4.04 s) + (0 m/s)
vᵧ = -39.6 m/s
Find the speed using Pythagorean theorem:
v = √(vₓ² + vᵧ²)
v = √((15.3 m/s)² + (-39.6)²)
v = 42.5 m/s
Answer:
Explanation:
Given
Initial speed 
distance traveled before coming to rest 
using equation of motion
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
for 
using same relation we get
divide 1 and 2 we get
So a distance if 213.32 ft is required to stop the vehicle with 80 mph speed
