Answer: <u>elastically</u> deformed or <u>non-permanently</u> deformed
Explanation:
According to classical mechanics, there are two types of deformations:
-Plastic deformation (also called irreversible or permanent deformation), in which the material does not return to its original form after removing the applied force, therefore it is said that the material was permanently deformed.
This is because the material undergoes irreversible thermodynamic changes while it is subjected to the applied forces.
-Elastic deformation (also called reversible or non-permanent deformation), in which the material returns to its original shape after removing the applied force that caused the deformation.
In this case t<u>he material also undergoes thermodynamic changes, but these are reversible, causing an increase in its internal energy by transforming it into elastic potential energy.</u>
<u />
Therefore, the situation described in the question is related to elastic deformation.
Answer:
1. :uniformly accelerated motion
2. .0m/s
Answer:
A. 19.6 m/s
B. 44.6 m
C. 5.0 s
D. -19.6 m/s
Explanation:
At the highest point, the stone's velocity is 0.
A. Given:
v = 0 m/s
t = 2 s
a = -9.8 m/s²
Find: v₀
v = at + v₀
0 = (-9.8)(2) + v₀
v₀ = 19.6 m/s
B. Given:
y₀ = 25 m
t = 2 s
v₀ = 19.6 m/s
a = -9.8 m/s²
Find: y
y = y₀ + v₀ t + ½ at²
y = 25 + (19.6)(2) + ½(-9.8)(2)²
y = 44.6 m
C. Given:
y₀ = 25 m
y = 0 m
v₀ = 19.6 m/s
a = -9.8 m/s²
Find: t
y = y₀ + v₀ t + ½ at²
0 = 25 + (19.6)t + ½(-9.8)t²
0 = 4.9t² − 19.6t − 25
t ≈ 5.0 s
D. Given:
v₀ = 19.6 m/s
a = -9.8 m/s²
t = 4 s
Find: v
v = at + v₀
v = (-9.8)(4) + 19.6
v = -19.6 m/s
The velocity is -19.6 m/s. If you want the speed, or magnitude of the velocity, take the absolute value: 19.6 m/s.
Answer:
1.body composition, (2) flexibility, (3) muscular strength, (4) muscular endurance, and (5) cardio respiratory endurance.
Explanation:
Answer:
a) 12.8 N
b) 3.2 m/s²
Explanation:
I'm guessing the period is 0.5π s.
Period of a spring in simple harmonic motion is:
T = 2π √(m/k)
Given T = 0.5π and m = 2 kg:
0.5π = 2π √(2/k)
0.25 = √(2/k)
0.0625 = 2/k
k = 32
The spring constant is 32 N/m, and the maximum displacement is 0.4 m. The maximum force can be found with Hooke's law:
F = kx
F = (32 N/m) (0.4 m)
F = 12.8 N
The acceleration can be found with Newton's second law:
∑F = ma
kx = ma
(32 N/m) (0.2 m) = (2 kg) a
a = 3.2 m/s²
