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3 years ago

A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy of 0.013 J.

Physics

1 answer:

Aleksandr [31]3 years ago

3 0

answer

v = 4.2 $\frac{m}{s}$

set up an equation

we can use the formula for kinetic energy since we know mass and kinetic energy

K = $\frac{mv^{2}}{2}$

v = $\sqrt{\frac{2K}{m} }$

values

K = 0.013 J

m = 1.5g = 0.0015 kg

plug in values

v = $\sqrt{\frac{2*0.013}{0.0015} }$

v = 4.2 $\frac{m}{s}$

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It's B because when you throw something it doesn't go up it slowly descends downward

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If the solar system shrank so that the sun were located just one centimeter from Earth, about how far away could you find the ne

DedPeter [7]

E S *

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The main thing to worry about here is units, so ill label everything out.
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Now this is where it gets fun, we need to put all the light years into centimeters.(theres alot)
In one light year, there are 9.461 * 10^17 centimeters.(the * in this case means multiplication) or 946,100,000,000,000,000 centimeters.

To convert we multiply the light years we found by the big number.
D'e,s'(Distance between earth and sun) = 1.496 * 10^13 centimeters
D'e,*'(Distance between earth and Proxima) = 4.014 * 10^18 centimeters

Now we scale things down, we treat 1.496 * 10^13 centimeters as a SINGLE centimeter, because that's the distance between the earth and the sun. So all we have to do is divide (4.014 * 10^18 ) by (1.496 * 10^13 ).
Why? because that how proportions work.

As a result, you get a mere 268335.7 centimeters.

To put that into perspective, that's only about 1.7 miles

A lot of my numbers came from google, so they are estimations and are not perfect, but its hard to be on really large scales.

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3 years ago

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jek_recluse [69]

Answer:

3 m/s

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Therefore, we can say that the correct answer is
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3 years ago

You want to slide a 0.39 kg book across a table. If the coefficient of kinetic friction is .21, what force is required to move t

uranmaximum [27]

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