Question

A paper clip that has a mass of 1.5 grams is thrown into the air and initially has a kinetic energy of 0.013 J.

Answer 1

answer

v = 4.2$\frac{m}{s}$

set up an equation

we can use the formula for kinetic energy since we know mass and kinetic energy

K = $\frac{mv^{2}}{2}$

v = $\sqrt{\frac{2K}{m} }$

values

K = 0.013 J

m = 1.5g = 0.0015 kg

plug in values

v = $\sqrt{\frac{2*0.013}{0.0015} }$

v = 4.2$\frac{m}{s}$