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VARVARA [1.3K]
2 years ago
12

The wavelength of light is given by the velocity divided by the frequency. the velocity of blue light is 300,000,000 m/sec, and

its frequency is 650,000,000,000,000 cycles per second. what is the wavelength of blue light? use scientific notation to make your calculation and express your answer.
Physics
2 answers:
s2008m [1.1K]2 years ago
5 0
<span>Electromagnetic radiation are represented in waves. Each type of wave has a certain shape and length. The distance between two peaks in a wave is called the wavelength. It is indirectly related to the frequency which is the number of wave that pass per unit of time. Wavelength is equal to the speed of light divided by the frequency. We calculate as follows:

Wavelength = </span>300,000,000 m/sec / <span>650,000,000,000,000 per second
Wavelength = 4.62x10^-4 m</span>
Oksi-84 [34.3K]2 years ago
4 0

<u>Answer:</u> The wavelength of the blue light is 4.615\times 10^{-7}m

<u>Explanation:</u>

To calculate the wavelength of the light, we use the formula:

\nu=\frac{c}{\lambda}

Where,

\nu = Frequency of the blue light = 6.5\times 10^{14}s^{-1}

\lambda = Wavelength of the blue light = ?

c = speed of the blue light = 3\times 10^8m/s

Putting values in above equation, we get:

\lambda =\frac{3\times 10^8m/s}{6.5\times 10^{14}s^{-1}}=4.615\times 10^{-7}m

Hence, the wavelength of the blue light is 4.615\times 10^{-7}m

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A 25 kg child plays on a swing having support ropes that are 2.20 m long. A friend pulls her back until the ropes are 42◦ from t
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Answer:

A) P.E = 138.44 J

B) The velocity of swing at bottom, v = 3.33 m/s

C) The work done, W = -138.44 J

Explanation:

Given,

The mass of the child, m = 25 Kg

The length of the swing rope, L = 2.2 m

The angle of the swing to the vertical position, ∅ = 42°

A) The potential energy at the initial position ∅ = 42° is given by the relation

                                P.E = mgh joule

Considering h  = 0 for the vertical position

The h at ∅ = 42° is  h = L (1 - cos∅)

                               P.E = mgL (1 - cos∅)

Substituting the given values in the above equation

                               P.E = 25 x 9.8 x 2.2 (1 - cos42°)

                                      = 138.44 J

The potential energy for the child just as she is released, compared to the potential energy at the bottom of the swing is, P.E = 138.44 J

B) The velocity of the swing at the bottom.

At bottom of the swing the P.E is completely transformed into the K.E

                  ∴                 K.E = P.E

                                     1/2 mv² = 138.44

                                     1/2 x 25 x v² 138.44

                                            v² = 11.0752

                                             v = 3.33 m/s

The velocity of the swing at the bottom is, v = 3.33 m/s

C) The work done by the tension in the rope from initial position to the bottom

             Tension on string, T = Force acting on the swing, F

                      W=L\int\limits^0_\phi{F} \, d \phi

                             =L\int\limits^0_\phi{mg.sin \phi} \, d \phi

                            = -Lmg[cos\phi]_{42}^{0}

                            = - 2.2 x 25 x 9.8 [cos0 - cos 42°]

                            = - 138.44 J

The negative sign in the in energy is that the work done is towards the gravitational force of attraction.

The work done by the tension in the ropes as the child swings from the initial position to the bottom of the swing, W = - 138.44 J

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3 years ago
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A supersonic jet, with a mass of 21,000 kg, departs from its home airbase with a velocity of 400 m/s due east. What is the jet’s
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Answer:

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Time taken by phillippe \frac{20}{3.5}+\frac{20}{3.5-1.5}

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Time taken by rena

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8 0
3 years ago
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