<span>1.0 m/s
Momentum = mass x velocity
Total Momentum before any collision = total momentum afterwards
4.0 x 3.0= 12 :g x momentum before (x g because using weight)
Afterwards, if the velocity of the two joined is v then we get:
'momentum x g'=12v
so 12v=12
so v=1m/s</span>
Answer:
the period of the 16 m pendulum is twice the period of the 4 m pendulum
Explanation:
Recall that the period (T) of a pendulum of length (L) is defined as:
![T=2\,\pi\,\sqrt{ \frac{L}{g} }](https://tex.z-dn.net/?f=T%3D2%5C%2C%5Cpi%5C%2C%5Csqrt%7B%20%5Cfrac%7BL%7D%7Bg%7D%20%7D)
where "g" is the local acceleration of gravity.
SInce both pendulums are at the same place, "g" is the same for both, and when we compare the two periods, we get:
![T_1=2\,\pi\,\sqrt{\frac{4}{g} } \\T_2=2\,\pi\,\sqrt{\frac{16}{g} } \\ \\\frac{T_2}{T_1} =\sqrt{\frac{16}{4} } =2](https://tex.z-dn.net/?f=T_1%3D2%5C%2C%5Cpi%5C%2C%5Csqrt%7B%5Cfrac%7B4%7D%7Bg%7D%20%7D%20%5C%5CT_2%3D2%5C%2C%5Cpi%5C%2C%5Csqrt%7B%5Cfrac%7B16%7D%7Bg%7D%20%7D%20%5C%5C%20%5C%5C%5Cfrac%7BT_2%7D%7BT_1%7D%20%3D%5Csqrt%7B%5Cfrac%7B16%7D%7B4%7D%20%7D%20%3D2)
therefore the period of the 16 m pendulum is twice the period of the 4 m pendulum.
Answer:
. The loop is pushed to the right, away from the magnetic field
Explanation
This decrease in magnetic strength causes an opposing force that pushes the loop away from the field
Answer:
If we are looking for evidence of something that exists outside of our visible Universe and leaves no trace within it, it seems that the idea of a Multiverse is fundamentally untestable. But there are all sorts of things that we cannot observe that we know must be true. Decades before we directly detected gravitational waves, we knew that they must exist, because we observed their effects.
Explanation:
Maybe helps lol