An osmolarity of saline solution is 308 mosmol/L.
m(NaCl) = 9 g; the mass of sodium chloride
V(solution) = 1 L; the volume of the saline solution
n(NaCl) = 9 g ÷ 58.44 g/mol
n(NaCl) = 0.155 mol; the amount of sodium chloride
number of ions = 2
Osmotic concentration (osmolarity) is a measure of how many osmoles of particles of solute it contains per liter.
The osmolarity = n(NaCl) ÷ V(solution) × 2
The osmolarity = 0.154 mol ÷ 1 L × 2
The osmolarity = 0.154 mol/L × 1000 mmol/m × 2
The osmolarity of the saline solution = 308 mosm/L.
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Answer:
it's a chemistry change
Explanation:
this is because heat is causing permanent changes and can no longer be changed back to its original atate
<span>There
are a number of ways to express concentration of a solution. This includes
molarity. Molarity is expressed as the number of moles of solute per volume of
the solution. So, we calculate as follows:
Molarity = 15.9 g BaCl2 ( 1 mol / 208.23 g ) / .375 L = 0.204 mol / L</span>
Answer:
NH₄⁺
H₂PO₄⁻
H₃O⁺
Explanation:
- An ion is an atom or molecule with a net electric charge due to the loss or gain of one or more electrons.
- Ion may be positively charged "cation" or negatively charged "anion".
- Neutral molecule has a net charge of zero.
<em>So, the species that are ions are: </em>
NH₄⁺
H₂PO₄⁻
H₃O⁺
Answer:
Mass of chlorine = 47.22 g
Explanation:
Given data:
Mass of sodium = 30.5 g
Mass of chlorine= ?
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
Number of moles of Na:
Number of moles = mass/molar mass
Number of moles = 30.5g/ 23 g/mol
Number of moles = 1.33 mol
Now we will compare the moles of Cl
₂ with Na from balance chemical equation.
Na : Cl
₂
2 : 1
1.33 : 1/2×1.33 = 0.665 mol
Mass of chlorine gas:
Mass = number of moles × molar mass
Mass = 0.665 mol × 71 g/mol
Mass = 47.22 g