Metallic bonds are formed by the valence electrons from the s and p orbitals of the interacting metal atoms delocalizing.
Answer:
0.165 mol·L⁻¹
Explanation:
1. Write the <em>chemical equation</em> for the reaction.
HNO₃ + KOH ⟶ KNO₃ + H₂O
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2. Calculate the <em>moles of HNO₃</em>
c = n/V Multiply each side by V and transpose
n = Vc
V = 0.027 86 L
c = 0.1744 mol·L⁻¹ Calculate the moles of HNO₃
Moles of HNO₃ = 0.027 86 × 0.1744
Moles of HNO₃ = 4.859 × 10⁻³ mol HNO₃
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3. Calculate the <em>moles of KOH
</em>
1 mol KOH ≡ 1 mol HNO₃ Calculate the moles of KOH
Moles of KOH = 4.859 × 10⁻³× 1/1
Moles of KOH = 4.859 × 10⁻³ mol KOH
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4. Calculate the <em>molar concentration</em> of the KOH
V = 29.4 mL = 0.0294 L Calculate the concentration
c = 4.859 × 10⁻³/0.0294
c = 0.165 mol·L⁻¹
The plants without any fertiliser could be the control, to see what the change in the independent variable (fertiliser) does to the growth of the plant (dependant variable).
Hope that helps.
Here ya go if you need the link we’re I found this answer key https://studylib.net/doc/8708211/exam-2---chemistry
