Answer:
3 s
Explanation:
velocity=initial velocity +a*t
34=10 + 8t
24=8t
t=3 s
Answer:
22m/s
Explanation:
Step one:
Given data
Initial velocity of roller coster u= 6 m/s
Final velocity v= 72m/s
time t= 3 seconds
Required
We want to solve for the acceleration of the roller coster
Step two:
From the formula
acceleration= v-u/t
substitute
a= 72-6/3
a=66
/3
a= 22 m/s
The cars acceleration 22m/s
<span>λ=h/(mv)
0.945*10^-10 = 6.626*10^-34/mv
mv = 6.626*10^-34/0.945*10^-10
v = 6.626*10^-34/(0,945*10^-10*1.6749*10^-27...
v = 6.626*10^-34/1.5828*10^-37
v = 4.186*10^3 m/s</span>
Answer:
doubled as well.
Explanation:
Using what I call "Method of Simplest Integers," insert all charges and distance as just 1 (ignore k, because it is a constant), so
Fe=k(1*1)/(1^2)=k(1)/1=k(1)
Since one of the charges is doubled,
Fe'=k(2*1)/(1^2)'k(2)/1=k(2)
Set Fe and Fe' side by side and compare their outcomes. cancel out k, because it's constant, and find out what multiple makes Fe becomes Fe'. In this case, it is 2. So the force would be doubled if one of the
Answer:
top speed = 17.25
Total height = 281.19 m
Explanation:
given data
mass = 75 kg
thrust = 160 N
coefficient of kinetic friction = 0.1
solution
we get here frictional force acting that is
frictional force =
.............1
frictional force = 0.1 × 75 × 9.8
frictional force = 73.5 N
and
Net force acting will be F = 160 - 73.5 N
F = 86.5 N
so
Acceleration in the First 15 second will be
F = ma .........2
86.5 = 75 × a
a = 1.15 m/s²
and
now After 15 second the velocity will be as
v = u + at ..........3
here u is 0
so v will be
V = 1.15 × 15
v = 17.25
and
now we get travels distance S in 15 s
s = u × t + 0.5 × a × t²
here u is 0
so distance s will be
s = 0.5 × a × t²
s = 0.5 × 1.15 × 15²
s = 129.37 m
and
now acceleration acting is
F =
m a =
a = ![\mu* g](https://tex.z-dn.net/?f=%5Cmu%2A%20g)
a = - 0.98
here it is negative it mean downward nature of acceleration
and
now we get distance s by this formula
V² - u² = 2 a s
here v velocity is 0 and
u initial velocity is 17.25 m/s
put here value
0 - 17.25² = 2 × (-0.98) × s
solve it we get
s = 151.82 m
so
Total height is
Total height = 129.37 m + 151.82 m
Total height = 281.19 m