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Irina-Kira [14]

3 years ago

6

g is incident on 3 successive sheets of polarizing material. The transmission axis of the first sheet is vertical. The transmiss

ion axis of the second sheet is at 30 degrees from vertical. The transmission axis of the third is horizontal. What is the intensity of the light emerging from the third sheet

1 answer:

murzikaleks [220]3 years ago

6 0

Answer:

The intensity of light passing from the third polarizer is 3Io/16.

Explanation:

The law of Malus is given by

$I=I_o cos^2\theta$

Let the incident intensity of light is Io.

The intensity of light passing from the first polarizer is

$I' = \frac{I_o}{2}$

The intensity of light passing from the second polarizer is

$I''=\frac{I_o}{2}\times cos^230 =\frac{3I_o}{8}$

The intensity of light passing from the third polarizer is

$I''' = \frac{3I_o}{8}\times cos^2 60\\\\\\I''' = \frac{3I_o}{16}$

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Answer:

Maximum height, h = 10 m

Explanation:

It is given that,

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Answer:

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German physicist Werner Heisenberg related the uncertainty of an object's position ( Δ x ) to the uncertainty in its velocity (

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According to the information given, the Heisenberg uncertainty principle would be given by the relationship

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Here,

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Rearranging to find the position

$\Delta x \geq \frac{h}{4\pi m\Delta v}$

Replacing with our values we have,

$\Delta x \geq \frac{6.625*10^{-34}m^2\cdot kg/s}{4\pi (9.1*10^{-31}kg)(0.01*10^6m/s)}$

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A baseball of radius r = 5.2 cm is at room temperature T = 20.8 C. The baseball has emissivity of ε = 0.86 and the Stefan-Boltzm

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Answer:

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Solution to the problem

And if we replace this into our equation of P we got:

$P = (4\pi r^2) \epsilon \sigma T^4$

And we can reorder this like that:

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