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Andreyy89
3 years ago
9

For the energy function V (x) = cos(x) for –[infinity] ≤x≤ +[infinity], find the values x=xsthat identify stable equilibria, and

the values x = xuthat identify unstable equilibria.
Physics
1 answer:
solmaris [256]3 years ago
8 0

Answer:

look it up

Explanation:

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Sholpan [36]

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Explanation:

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Which physical property refers to the temperature at which a substance in a solid-state transforms to a liquid state?
solmaris [256]

Answer:

C: Melting point

Explanation:

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What is the potential energy of a 150 kg diver standing on a diving board that is 10 m high? The potential energy is J
iris [78.8K]

The formula for potential energy would be PE = mgh Where: m is the mass; g is the acceleration due to gravity, and h would be height. So plugging in the data: PE = 150kg × 9.8 m/s^2 × 10m = 14700 Joules would be the potential energy for this problem. <span>
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4 years ago
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If you applied a 11 N force to a box and made it travel 108 m in 7
snow_lady [41]

Explanation:

due to the local people in the advantage and the value of that house so that there were no people this answer was belonging to define in refinery of the circuit

6 0
4 years ago
A horizontal force of magnitude 31.3 N pushes a block of mass 4.30 kg across a floor where the coefficient of kinetic friction i
Ostrovityanka [42]

Answer:

W_{F} =  +119.6 J : Work done by horizontal force

W_{Ff} =  -96.42 J : Work done by friction force

W_{n} =   23.18 J :  Net work

Explanation:

Work theory

Work is the product of a force applied to a body and the displacement of the body in the direction of this force.

Thus. The work is equal to the product of the force by the distance (d) and by the cosine of the angle ( α) that exists between the direction of the force (F) and the direction that travels the point or the object that moves:

W= F*d*cosα Formula (1)

The work is positive (W+) if the force goes in the same direction of movement.

The work is negative (W-)if the force goes in the opposite direction to the movement

Net work  (Wn)

Net work is defined as the sum of the work done from an initial place to an end point of the trajectory, for each of the individual forces to which the  system is subjected.

Problem development

We determine the forces that perform work:

in formula (1 )we observe that the forces that perform work are the forces parallel to displacement. that is α = 0.

For this case they are the horizontal force (F) and the frictional force (Ff)

F=31.3 N : Horizontal force

Ff=μk*N , μk:coefficient of kinetic friction  , N : Normal force

N=W  

W: block weight  W= m*g, m:  block mass , g: acceleration due to gravity

W= 4.30 kg* 9.8 m/s² = 42.14 N

Ff= 0.599*42.14 N= 25.24 N : Frictional force

Calculating of the Net work  (Wn)

W_{n} = W_{F} +W_{Ff}

W_{F} =   31.3N*3.82 m

W_{F} =  119.6 N*m

W_{F} =  +119.6 J

W_{Ff} =  -25.24N*3.82m

W_{Ff} =  -96.42 N* m

W_{Ff} =  -96.42 J

W_{n} = W_{F} +W_{Ff}

W_{n} = ( 119.6  -96.42) N*m

W_{n} =   23.18 N*m

W_{n} =   23.18 J

8 0
3 years ago
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