Answer:
Part a)
Time to reach the maximum height is given as
B)
Maximum height of the bullet is
C)
Horizontal range of the bullet is
Part d)
Final velocity of the bullet is v = 600 m/s at 30 degree
Explanation:
A) As we know that velocity of the bullet is
v = 600 m/s
So we have
Now time to reach the maximum height is given as
B) As we know that the object have zero final speed in y direction
C)
Now the horizontal displacement of the object in total time of flight is known as range of projectile
So we have
Part d)
As we know that the final height is same as that of initial So it will strike the ground at same velocity as that of initial velocity
So we have
v = 600 m/s at 30 degree
Answer:
The correct option is C
Explanation:
According to third equation of motion, v
2
=u
2
+2ax
Here, u=0 m/s
a=−g and x=−h
Negative sign indicates downward direction. Displacement and acceleration both are downwards.
So,v=±
2(−g)(−h)
We take minus sign because it is downwards.
v=−
2gh
After bouncing. velocity becomes 80% of v, i.e.,
v
′
=+0.8
2gh
(positive sign because the direction of ball has reversed after bouncing and is upwards.
Applying third equation of motion again, for u=v
′
, v=0 and a=−g
v
2
=u
2
+2×a×x
Thus,
0=0.64(2gh)+2(−g)x
or
x=0.64h
Answer:
It's STERIC NUMBER.
Explanation:
The steric number is the number of shared pairs of electrons on a central atom of a molecule (σ sigma bond) plus the number of lone pairs on the central atom.