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3 years ago

9

For the energy function V (x) = cos(x) for –[infinity] ≤x≤ +[infinity], find the values x=xsthat identify stable equilibria, and

the values x = xuthat identify unstable equilibria.

1 answer:

solmaris [256]3 years ago

8 0

Answer:

look it up

Explanation:

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Answer:

The activation energy is $Q = 328.31 \ K J/mol$

Explanation:

From the question we are told that

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T is the temperature

For the first rate constant

$k_1 = Ce ^{-\frac{Q}{RT_1} }$

For the second rate constant

$k_2 = Ce ^{-\frac{Q}{RT_2} }$

Now the ratio between the two given rate constant is

$\frac{k_1 }{k_2} = e^{(\frac{Q}{R} [\frac{1}{\frac{T_2 - 1}{T_1} } ] )}$

=> $ln [\frac{k_1}{k_2} ] = \frac{Q}{R} * [\frac{1}{\frac{T_2 -1}{T_1} } ]$

substituting values

$ln [\frac{1.05 *10^{-8}}{2.95 *10^{-4}} ] = \frac{Q}{8.314} * [\frac{1}{\frac{673 -1}{573} } ]$

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3 years ago

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Answer:

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The ratio is obtained by multiplying each side by $\frac{m_{c}}{m_{b}}$ :

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The value of this ratio is:

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