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Andreyy89
3 years ago
9

For the energy function V (x) = cos(x) for –[infinity] ≤x≤ +[infinity], find the values x=xsthat identify stable equilibria, and

the values x = xuthat identify unstable equilibria.
Physics
1 answer:
solmaris [256]3 years ago
8 0

Answer:

look it up

Explanation:

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Define linear expansivity
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Linear expansivity is a type of thermal expansion. It is described by a fraction that represents the fractional increase in length of a thin beam of a material exposed to a temperature increase of one degree Celsius. ... Linear expansivity is used in many real world applications.

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elements are organized based on their properties on a chart called modern periodic table which of the following statements is tr
Illusion [34]

Answer:

Elements are arranged in the table by increasing atomic number.

Explanation:

In the modern periodic table, each element is represented by its chemical symbol. The number above each symbol is its atomic number.

8 0
3 years ago
Find the momentum of a particl with a mass of one gram moving with half the speed of light.
joja [24]

Answer:

129900

Explanation:

Given that

Mass of the particle, m = 1 g = 1*10^-3 kg

Speed of the particle, u = ½c

Speed of light, c = 3*10^8

To solve this, we will use the formula

p = ymu, where

y = √[1 - (u²/c²)]

Let's solve for y, first. We have

y = √[1 - (1.5*10^8²/3*10^8²)]

y = √(1 - ½²)

y = √(1 - ¼)

y = √0.75

y = 0.8660, using our newly gotten y, we use it to solve the final equation

p = ymu

p = 0.866 * 1*10^-3 * 1.5*10^8

p = 129900 kgm/s

thus, we have found that the momentum of the particle is 129900 kgm/s

6 0
3 years ago
A skater has rotational inertia 4.2 kg.m2 with his fists held to his chest and 5.7 kg.m2 with his arms outstretched. The skater
Fynjy0 [20]

Answer:

6.13428 rev/s

Explanation:

I_f = Final moment of inertia = 4.2 kgm²

I = Moment of inertia with fists close to chest = 5.7 kgm²

\omega_i = Initial angular speed = 3 rev/s

\omega_f = Final angular speed

r = Radius = 76 cm

m = Mass = 2.5 kg

Moment of inertia of the skater is given by

I_i=I+2mr^2

In this system the angular momentum is conserved

L_f=L_i\\\Rightarrow I_f\omega_f=I_i\omega_i\\\Rightarrow \omega_f=\dfrac{I_i\omega_i}{I_f}\\\Rightarrow \omega_f=\dfrac{(5.7+2\times 2.5\times 0.76^2)3}{4.2}\\\Rightarrow \omega_f=6.13428\ rev/s

The rotational speed will be 6.13428 rev/s

5 0
2 years ago
Which letter in the figure below marks 1 millimeter
kondor19780726 [428]
Do you have a picture then I could determine 1 millimeter
5 0
3 years ago
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