2 years ago

I need help please and thanks

Physics

1 answer:

asambeis [7]2 years ago

6 0

Answer:

Explanation:

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An electron moving with a velocity = 5.0 × 10 7 m/s enters a region of space where perpendicular electric and a magnetic fields

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Answer:

The magnetic field is $2 \times 10^{-4}$ T

Explanation:

Given:

Velocity of electron $v = 5 \times 10^{7} \frac{m}{s}$

Electric field $E = 10^{4} \frac{V}{m}$

The force on electron in magnetic field is given by,

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The force on electron in electric field is given by,

$F = qE$ ......(2)

Compare both equation,

$qE = qvB \sin \theta$

Here $\sin \theta = 1$

$E = vB$

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$B = \frac{10^{4} }{5 \times 10^{7} }$

$B = 2 \times 10^{-4}$ T

Therefore, the magnetic field is $2 \times 10^{-4}$ T

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3 years ago

Water displacement is used to find what? a. volume b. density

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A long electric cable is suspended above the earth and carries a current of 345 A parallel to the surface of the earth. The eart

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0.906 N

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Formula for magnetic force acting on current carrying cable:

$F = IBLsin(\theta)$

Where I = 345A is the current in the wire, B = $5.6*10^{-5} T$ is the magnetic magnitude generated by Earth. L = 46.9 m is the cable length. $\theta = 88.2^o$ is the angle between vector B and cable direction.

$F = 345*5.6*10^{-5}*46.9*sin(88.2^o)$

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