Answer:
16.935 N
Explanation:
In order to make the box start moving, the level force applied on the box (F) must be greater than the force of static friction that keeps the box at rest, which is equal to

where
is the coefficient of static friction
(mg) = 30 N is the weight of the box
Therefore, the condition for F must be:

So, the applied force must be greater than this value.
Answer:
Height = 53.361 m
Explanation:
There are two balloons being thrown down, one with initial speed (u1) = 0 and the other with initial speed (u2) = 43.12
From the given information we make the following summary
= 0m/s
= t
= 43.12m/s
= (t-2.2)s
The distance by the first balloon is

where
a = 9.8m/s2
Inputting the values

The distance traveled by the second balloon

Inputting the values

simplifying

Substituting D of the first balloon into the D of the second balloon and solving

Now we know the value of t. We input this into the equation of the first balloon the to get height of the apartment

Metamorphic rock this possess often occurs in the mantle
Answer:
La velocidad media es 5
, que equivale a 1.389 
Explanation:
La velocidad es una magnitud física que expresa la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello.
La velocidad media relaciona el cambio de la posición con el tiempo empleado en efectuar dicho cambio. Por lo que se calcula como la distancia recorrida por un objeto dividido por el tiempo transcurrido:

En este caso:
- distancia= 10 km= 10,000 m (siendo 1 km= 1,000 m)
- tiempo= 2 h= 7,200 s (siendo 1 h= 3,600 s)
Entonces, reemplazando en la definición de velocidad media:

Resolviendo se obtiene:

<u><em>La velocidad media es 5 </em></u>
<u><em>, que equivale a 1.389 </em></u>
<u><em></em></u>