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svp [43]
3 years ago
6

AV 5. How many grams are in 0.52 moles of H3PO4?

Chemistry
1 answer:
Hoochie [10]3 years ago
3 0

Answer:

50.96g

Explanation:

Given parameters:

Number of moles of H₃PO₄   = 0.52moles

Unknown:

Mass of the compound  = ?

Solution:

To find the mass of the compound:

    Mass  = number of moles x molar mass of H₃PO₄

Molar mass of H₃PO₄ = 3(1) + 31 + 4(16)  = 98g/mol

  Mass  = 0.52 x 98  = 50.96g

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LuckyWell [14K]

Q.1-

Given,

mass - 10grams

volume - 24 cm³

density = mass/volume

density = 10/24

density = 0.416 g/cm³

Q.2-

Given,

mass - 700grams

volume - 1100cm³

density = mass/volume

density = 700/1100

density = 0.6363 g/cm³

5 0
3 years ago
Why there are only seven crystal systems??? why not other number
Anastasy [175]
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3 years ago
Complete and balance the following equations. If no reaction occurs, write NR:(d) ClF(g) + F₂(g) →
kumpel [21]

A reaction occurs between the two gases Chlorine monofluoride (ClF) and Fluorine (F₂) when they are added together and as a result of the reaction a compound named, Chlorine trifluoride (ClF₃) is formed.

The reaction which occurs by addition of Chlorine monofluoride (ClF) and Fluorine (F₂) is as follows -

ClF (g) + F₂ (g) = ClF₃ (l)

When one molecule of Chlorine monofluoride (ClF) reacts with one molecule of Fluorine (F₂) gas, both the gases react together to form one molecule of Chlorine trifluoride (ClF₃) which is a liquid. Therefore, the above reaction is already balanced.

Chlorine trifluoride (ClF₃) is a greenish-yellow liquid which acts as an important fluorinating agent and is also an interhalogen compound (compounds that are formed by mixing two different halogen compounds together). Other than it's liquid state ClF₃ also can exist as a colorless gas. This compound ClF₃ is a very toxic, very corrosive and powerful oxidizer used as an igniter and propellent in rockets.

Learn more about Chlorine monofluoride (ClF) here-

brainly.com/question/17129650

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8 0
2 years ago
Can someone please please help me out ?
GarryVolchara [31]

Answer:

4.823 x 10^-19 J

Explanation:

Energy is calculated by E = hv where h - Planck's constant in joule.s

v - frequency.

in this particular question the wave length is 4.12 x 10^-7 m. to exhaustively use this we need a relation between wave length & frequency. c=wv where C is approximately 3 x 10^8m/s

-v = c/w = 3x10^8m/s / 4.12 x 10^-7m = 7.28 x 10^14 Hz or 1/sec

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6 0
2 years ago
Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to
vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

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Now set up and solve a stoichiometric conversion from moles of H_2SO_4  to grams of NaHCO_3. As, the molar mass of NaHCO_3 is 84.01 g/mol.

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So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

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