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2 years ago

AV 5. How many grams are in 0.52 moles of H3PO4?

Chemistry

1 answer:

Hoochie [10]2 years ago

3 0

Answer:

50.96g

Explanation:

Given parameters:

Number of moles of H₃PO₄ = 0.52moles

Unknown:

Mass of the compound = ?

Solution:

To find the mass of the compound:

Mass = number of moles x molar mass of H₃PO₄

Molar mass of H₃PO₄ = 3(1) + 31 + 4(16) = 98g/mol

Mass = 0.52 x 98 = 50.96g

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2. Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP, is needed to com

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first, we have to convert grams to molecules using the molar mass, and then use mole to mole ratio from the balanced equation.

molar mass of Na= 23.0 g/mol
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calculations:

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RideAnS [48]

Answer:

1) Favor formation of reactant

2) Favor formation of product

3) Favor formation of product

4) Favor formation of product

5) Favor formation of product

Explanation:

The reaction is $AgBr(s)--->Ag^{+}(aq)+Br^{-}(aq)$

The reaction is endothermic

1. Adding hydrobromic acid (HBr)

It will increase the amount of bromide ion. Bromide ion is one of the product so it will favor formation of reactant.

2. Lowering the concentration of bromide (Br-) ions

As we are decreasing the the concentration of product it will favor formation of more products

3. Heating the concentrations

If we are heating the mixture, it will increase the temperature and it will favor endothermic reaction. Thus will favor formation of product.

4. Adding solid silver bromide (AgBr)

If we are adding silver bromide it means we are increasing the concentration of reactant, it will favor formation of products

5. Removing silver (Ag+) ions

Removing silver ions means we are decreasing the concentration of product thus it will favor formation of products.

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m=5g

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density=m/v

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