<span>In crystallography, the terms crystal system, crystal family, and lattice system each refer to one ... In total there are seven crystal systems: triclinic, monoclinic, orthorhombic, ..... A polar crystal possess a "unique" axis (found in no other directions) such ... lattices in three dimensions; each can apply in one lattice system only.</span><span>
</span>
A reaction occurs between the two gases Chlorine monofluoride (ClF) and Fluorine (F₂) when they are added together and as a result of the reaction a compound named, Chlorine trifluoride (ClF₃) is formed.
The reaction which occurs by addition of Chlorine monofluoride (ClF) and Fluorine (F₂) is as follows -
ClF (g) + F₂ (g) = ClF₃ (l)
When one molecule of Chlorine monofluoride (ClF) reacts with one molecule of Fluorine (F₂) gas, both the gases react together to form one molecule of Chlorine trifluoride (ClF₃) which is a liquid. Therefore, the above reaction is already balanced.
Chlorine trifluoride (ClF₃) is a greenish-yellow liquid which acts as an important fluorinating agent and is also an interhalogen compound (compounds that are formed by mixing two different halogen compounds together). Other than it's liquid state ClF₃ also can exist as a colorless gas. This compound ClF₃ is a very toxic, very corrosive and powerful oxidizer used as an igniter and propellent in rockets.
Learn more about Chlorine monofluoride (ClF) here-
brainly.com/question/17129650
#SPJ4
Answer:
4.823 x 10^-19 J
Explanation:
Energy is calculated by E = hv where h - Planck's constant in joule.s
v - frequency.
in this particular question the wave length is 4.12 x 10^-7 m. to exhaustively use this we need a relation between wave length & frequency. c=wv where C is approximately 3 x 10^8m/s
-v = c/w = 3x10^8m/s / 4.12 x 10^-7m = 7.28 x 10^14 Hz or 1/sec
now we can simply use Planck's constant in E=hv =
(6.626 x 10^-34) x (7.28 x 10^14Hz) = 4.823 x 10^-19 J.
Explanation:
We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.
Next we will calculate how many moles of 
are present in 85.00 mL of 1.500 M sulfuric acid.
As, Molarity = 
1.500 M = 
n = 0.1275 mol
Now set up and solve a stoichiometric conversion from moles of to grams of 
. As, the molar mass of is 84.01 g/mol.
= 21.42 g
So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.
