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Dovator [93]
2 years ago
7

HELP ASAP I WILL GIVE BRAINLIEST

Chemistry
1 answer:
alina1380 [7]2 years ago
3 0

Answer:

it can last for 30 minutes

Explanation:

because it is very good at giving off heat, extothermal heat can last for quite a while.

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Given 50.0 grams of Strontium, find grams of Phosphorus required for complete reaction
Sveta_85 [38]

Answer:

                     Mass = 11.78 g of P₄

Explanation:

                     The balance chemical equation is as follow:

                                          6 Sr + P4 → 2 Sr₃P₂

Step 1: Calculate moles of Sr as;

Moles = Mass / M/Mass

Moles = 50.0 g / 87.62 g/mol

Moles = 0.570 moles

Step 2: Find moles of P₄ as;

According to equation,

6 moles of Sr reacted with  =  1 mole of P₄

So,

0.570 moles of Sr will react with  =  X moles of P₄

Solving for X,

X = 1 mol × 0.570 mol / 6 mol

X = 0.0952 mol of P₄

Step 3: Calculate mass of P₄ as,

Mass = Moles × M.Mass

Mass = 0.0952 mol × 123.89 g/mol

Mass = 11.78 g of P₄

8 0
2 years ago
19. Which food tastes acidic?<br> O cucumber<br> O celery<br> o Domato<br> O radish
devlian [24]
Radishhhhhhhhhhhhhhhhhhhhhhhhh
6 0
3 years ago
Read 2 more answers
In an isolated system, mass can neither be<br> created or destroyed.<br> ube<br> FALSE<br> TRUE
Marina86 [1]

Answer:

True

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Hope it helps

5 0
3 years ago
A liquid has a _____.
guajiro [1.7K]

Answer:

definite volume

Explanation:

hope this helps!❆

3 0
2 years ago
Read 2 more answers
Can someone help me? It needs to have a diagram that has arrows.
daser333 [38]

Answer: The enthalpy change for formation of butane is -125 kJ/mol

Explanation:

The balanced chemical reaction is,

C_4H_{10}(g)+\frac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)

The expression for enthalpy change is,

\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]

Putting the values we get :

\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]

-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]

H_f_{C_4H_{10}=-125kJ/mol

Thus enthalpy change for formation of butane is -125 kJ/mol

5 0
3 years ago
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