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3 years ago

A swimmer speeds up from 1.1 m/s to 3.2 m/s during the last 13.0 seconds of the race. What is the acceleration of the swimmer?

Physics

1 answer:

rodikova [14]3 years ago

7 0

Answer:

a = 0.16 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

$v_{f}=v_{o}+a*t\\$

where:

Vf = final velocity = 3.2 [m/s]

Vo = initial velocity = 1.1 [m/s]

t = time = 13 [s]

a = acceleration [m/s²]

Now replacing:

$3.2=1.1+a*13\\2.1=13*a\\a=0.16[m/s^{2} ]$

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A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process? A. velocity and

dezoksy [38]

Answer:

A. velocity and wavelength

Explanation:

When a wave travels from one medium to another it undergoes a change in direction and this is referred to as refraction.
Refraction is the bending of a wave or a change in direction of a wave as it travels from one medium to another. Refraction is accompanied by change in velocity and wavelength of a wave.
Velocity of a wave is proportional to the wavelength of the wave therefore, if the velocity of a wave changes the the wavelength will also change proportionally to the velocity.

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4 years ago

A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s,

Serhud [2]

By using the equation speed = distance/time we can solve for distance. The speed is 4 m/s and the time is 12 seconds. We need to rearrange the equation to Speed * Time = distance. 4(12) = 48; 48 = distance. The cliff is 48 meters high.

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3 years ago

A hunter stands on a frozen pond (frictionless) and fires a 4.20g bullet at 965m/s horizontally.The mass of hunter + gun is 72.5

Afina-wow [57]

Answer:

The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.

Explanation:

Given;

mass of bullet, m₁ = 4.2 g = 0.0042 kg

mass of hunter + gun = 72.5 kg

velocity of the bullet, u = 965 m/s

Momentum of the bullet when it was fired;

P = mv

P = 0.0042 x 965

P = 4.053 kg.m/s

Determine the recoil velocity of the hunter.

Total momentum = sum of the individual momenta

Total momentum = momentum of the bullet + momentum of the hunter

Apply the principle of conservation of momentum, sum of the momentum is equal to zero.

$P_{hunter} + P_{bullet} = 0\\\\P_{hunter} = -P_{bullet}\\\\72.5v = -4.053\\\\v = \frac{-4.053}{72.5} \\\\v = - 0.056 \ m/s\\\\Thus, the \ recoil \ velocity \ of \ the \ hunter \ is \ 0.056 \ m/s, \ in \ opposite \ direction \ of \ the \ bullet.$

Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.

6 0

4 years ago

NEED HELP ASAP

andriy [413]

Answer:

the battery, I think this answer

3 0

3 years ago

If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positi

Alex

If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away

The muzzle velocity of the bullet is 275 m/s

Answer:

y = -1.1109 m

Explanation:

Range = $\frac{v^2sin2\theta}{g}$