Explanation:
Given that,
The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.
The mass of each orange is 198 g
We know that,
1 kg = 1000 g
10.222 kg = 10.222×1000 g
Let there are n number of oranges. So,

It means she can send 52 oranges and it is maximum quantity.
Answer:
D = 25 miles
Explanation:
To solve this problem, we just need to know how much time it took both bicyclists to collide and that will be the same amount of time that the bee flew at 25miles per hour. With those values we could calculate the distance it traveled.
Since both bicyclists collide, we know that Xa=Xb, so:
Xa = V*t = 10*t and Xb = 20 - V*t = 20 - 10*t
10*t = 20 - 10*t Solving for t:
t = 1 hour Now we can calculate the distance for the bee:
D = Vbee * t = 25 * 1 = 25 miles
Answer:
The best estimate of the depth of the well is 2.3 sec.
Explanation:
Given that,
Record time,





We need to find the best estimate of the depth of the well
According to record time,
We can write of the record time





Here, all time is nearest 2.3 sec.
So, we can say that the best estimate of the depth of the well is 2.3 sec.
Hence, The best estimate of the depth of the well is 2.3 sec.
A elephant kicks a 5.0\,\text {kg}5.0kg5, point, 0, start text, k, g, end text stone with 150\,\text J150J150, start text, J, en
S_A_V [24]
The speed of the stone is 7.7 m/s
Explanation:
The kinetic energy of a body is the energy possessed by the body due to its motion. Mathematically,

where
m is the mass of the body
v is its speed
For the stone in this problem, we have:
K = 150 J is its kinetic energy
m = 5.0 kg is its mass
Re-arranging the equation for v, we find the speed of the stone:

Learn more about kinetic energy:
brainly.com/question/6536722
#LearnwithBrainly
Answer:
The answer is explained below.
Explanation:
All the point on the disk has same angular acceleration. Here, the point P is at the midway between the center and the rim of the disk and the point Q is at rim of the disk.
So, the distance of the point Q from the axis is twicee the distance of the point P from the axis.
<em>Rp - R</em>
<em>Rq - 2R</em>
The linear acceleration is
α2 - Rα
So, the linear acceleration of Q is twice as great as the linear acceleration of P.
The speed of the particle when it is in the circular motion depends on the radius of the particle.
In this case, the speed of point Q is twice the speed of point P.