The rate of change of d(t) at t = 2 and t = 6 is the ratio between the change of distance (difference between the distances) to the time elapsed. That is,
r = (576 - 64) / (6 - 2) = 128 ft /s
The rate of change is equal to 128 ft/s and this represents the average speed at this time interval.
Distance can be equal to displacement ... if the motion is all in a straight line ... but distance can never be greater than displacement.
Answer:
1.03m/s
Explanation:
According to the question
Fdrag = bv²
now Fdrag = weight of the box
that is Fdrag = mg
where m = mass of the box, 0.6 Kg
and g = acceleration due to gravity
thus,
Fdrag = bv² becomes
mg = bv²
making v the subject of formula
v = 1.03m/s
Avogadros law is applied when temperature and pressure remain constant, and details the direct relationship between moles and volume in this circumstance
