In which of the following is positive work done by a person on a suitcase

A car travels from point a to point b, moving in the same direction but with a non-constant speed. the first half of the distanc

Naddik [55]

You have to devide and add evreythuy butthe answer is 464

6 0

3 years ago

Read 2 more answers

If a wooden ball has a mass of 2.4g and a volume of 6cm3. What is it’s density?

Luba_88 [7]

Answer:

<h3>The answer is 0.4 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 2.4 g

volume = 6 cm³

We have

$density = \frac{2.4}{6} \\$

We have the final answer as

Hope this helps you

5 0

3 years ago

Sara wanted to paddle her canoe in the swamp to see alligators. She dragged the 45 Newton canoe for 36 seconds down the boardwal

Dafna11 [192]

Answer:

C .96 meters

Explanation: i just had this question

7 0

3 years ago

Electric fish generate current with biological cells called electroplaques, which are physiological emf devices. The electroplaq

Harlamova29_29 [7]

Answer:

current in water = 0.924 A

Explanation:

Let the current in each row be i.

Thus, current in water is contributed by each row and total current in water becomes 140i.

We are given;

emf of each electroplaque = 0.15 V

Number of electroplaques = 5000

internal resistance = 0.25 Ω

resistance = 800Ω

Applying Kirchoff's Voltage Law to row and water, we have;

5000E − (5000r)i − 800(140i) = 0

Rearranging;

5000E = (5000r)i + 800(140i)

Plugging in the relevant values;

5000 x 0.15 = i((5000 x 0.25) + 112,000)

750 = 113,250i

i = 750/113,250

i = 0.0066 A

Recall earlier, the current in water is 140i.

Thus, current in water = 140 x 0.0066

= 0.924

5 0

3 years ago

Help!!!, combination circuits, Physics

Kaylis [27]

Current and voltage on each resistor:

$I_1 = 3.98 A, V_1 = 3.98 V$

$I_2=0.015 A, V_2 = 0.075 V$

$I_3 = 0.4 A, V_3 = 0.4 V$

$I_4 = 0.385 A, V_4 = 0.77 V$

$I_5 = 0.585 A, V_5 = 1.17 V$

$I_6 = 3.01 A, V_6 = 6.02 V$

$I_7 = 0.97 A, V_7 = 4.85 V$

Explanation:

In order to solve the circuit, we first have to find the equivalent resistance of the whole circuit, then the total current, and then we can proceed finding the current and the voltage for each resistor.

We start by calculating the equivalent resistance of resistors 2 and 3, which are in parallel:

$R_{23}=\frac{R_2R_3}{R_2+R_3}=\frac{(5)(1)}{5+1}=0.833\Omega$

This resistor is in series with resistor 4, so:

$R_{234}=R_{23}+R_4=0.833+2.0=2.833\Omega$

This resistor is in parallel with resistor 5, therefore:

$R_{2345}=\frac{R_{234}R_5}{R_{234}+R_5}=\frac{(2.833)(2.0)}{2.833+2.0}=1.172\Omega$

This resistor is in series with resistor 7, so:

$R_{23457}=R_{2345}+R_7=1.172+5.0=6.172\Omega$

This resistor is in parallel with resistor 6, so:

$R_{234567}=\frac{R_{23457}R_6}{R_{23457}+R_6}=\frac{(6.172)(2.0)}{6.172+2.0}=1.510\Omega$

Finally, this combination is in series with resistor 1:

$R_{eq}=R_1+R_{234567}=1.0+1.510=2.510\Omega$

We finally found the equivalent resistance of the circuit. Now we can find the total current in the circuit, which is also the current flowing through resistor 1:

$I_1=\frac{V}{R_{eq}}=\frac{10}{2.510}=3.98 A$