The rock it traveling really, really fast.
It is hard to exactly determine how fast bc u need the height of the cliff and how big the rock is.
Hope this helps and can I get brainliest answer!
1.14 km = Distance
2.30 m/s = Speed
5.12 cm/s2 = Speed
6.150 mph = Distance
8.3.2 sec = Speed
9.25 ft = Distance
It should be Constant speed. The line goes straight & doesn’t change within the graph.
<span>You are given a QL = -26 μC charge that is placed on the x-axis at x = - 0.2 m and a QR = 26 μC charge that is placed at x = +0.2 m. The answers are:
The x-component of the electric field at x = 0 m and y = 0.2 m is 3.
The y-component of the electric field at x = 0 m and y = 0.2 m is 2.
</span>
Answer:
a)
b)S= 46.4 cm
Explanation:
Given that
Velocity = 16 Km/s
V= 16,000 m/s
E= 27 mV/m
E=0.027 V/m
d= 22.5 cm
d= 0.225 m
a)
lets time taken by electron is t
d = V x t
0.225 = 16,000 t

b)
We know that
F = m a = E q ------------1
Mass of electron ,m

Charge on electron

So now by putting the values in equation 1




Here initial velocity u= 0 m/s

S=0.464 m
S= 46.4 cm
S is the deflection of electron.