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3 years ago

PLEASE HELP ILL GIVE BRAINLIST AND POINTS (I don’t mind how long it needs to be)

Chemistry

2 answers:

lapo4ka [179]3 years ago

3 0

Answer:

When two or more atoms chemically bond together, they form a molecule. When molecules are made from two or more different kinds of atoms, the substances are called compounds. If molecules are made from only one kind of atom, the substances are elements.

Explanation:

gave an explanation in my answer XD anyway hope I helped. Have a good day!

Morgarella [4.7K]3 years ago

3 0

Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

Please mark brainliest

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A chemist uses hot hydrogen gas to convert chromium(III) oxide to

Darya [45]

Answer: 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$

Explanation:

The reaction equation for given reaction is as follows.

$Cr_{2}O_{3} + 3H_{2} \rightarrow 2Cr + 3H_{2}O$

Here, 1 mole of $Cr_{2}O_{3}$ reacts with 3 moles of $H_{2}$ .

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide $(Cr_{2}O_{3})$ is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of $Cr_{2}O_{3}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol$

Now, moles of $H_{2}$ .given by 0.5 mol of $Cr_{2}O_{3}$ is calculated as follows.

$0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}$

As molar mass of $H_{2}$ is 2.016 g/mol. Therefore, mass of $H_{2}$ is calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g$

Thus, we can conclude that 3.024 g grams of hydrogen are needed to convert 76 grams of chromium(III) oxide, $Cr_{2}O_{3}$ .

7 0

3 years ago

How many atoms of S are in the following formula: 3Na(SO4)2 1) 6 2) 8 3) 3 4) 5

larisa [96]

Answer:

Explanation:

7 0

3 years ago

If 88.0 L of natural gas, which is essentially methane (CH4), undergoes complete combustion at 720. mm Hg and 22ºC, how many gra

mr_godi [17]

126 grams of H2O is formed.

Explanation:

Data given:

volume of the gas = 88 Liters

pressure = 720 mm Hg or 0.947 atm

temperature T = 22 Degrees or 295.15 K

R = 0.08021 atm L/mole K

n =?

The formula is used is of ideal gas law to know the number of moles of CH4 undergoing combustion.

PV = nRT

n = $\frac{PV}{RT}$

putting the values in the equation

= 0.947 X 88/ 0.08021 X 295.15

n = 3.5 moles

balanced reaction for combustion of methane

CH4 + O2 ⇒ CO2 + 2H20

1 mole of CH4 undergoes combustion to form 2 moles of water

3.5 moles will give x moles of water

2/1 = x/3.5

x = 7 moles of water (atomic mass of water = 18 gram/mole)

mass = atomic mass x number of moles

mass = 18 x 7

=126 grams of water is formed.

7 0

4 years ago

Is my current answer correct? if not, please correct me

MAVERICK [17]

Answer:

Yes you’re correct :)

Explanation:

4 0

3 years ago

Read 2 more answers

Please help

Kay [80]

Answer:

Can you post the pic to it so I can give you more info?

Explanation:

5 0

3 years ago