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3 years ago

PLEASE HELP ILL GIVE BRAINLIST AND POINTS (I don’t mind how long it needs to be)

Chemistry

2 answers:

lapo4ka [179]3 years ago

3 0

Answer:

When two or more atoms chemically bond together, they form a molecule. When molecules are made from two or more different kinds of atoms, the substances are called compounds. If molecules are made from only one kind of atom, the substances are elements.

Explanation:

<em> gave an explanation in my answer XD anyway hope I helped. Have a good day!</em>

Morgarella [4.7K]3 years ago

3 0

Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

Please mark brainliest

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3 years ago

Calculate the freezing point of a solution made from 220g of octane (C Hua), molar mass = 114,0 gmol dissolved in 1480 g of benz

stiv31 [10]

Answer: Freezing point of a solution will be $-1.16^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(5.50-T_f)^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

$(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}$

$(5.50-T_f)^0C=6.68$

$T_f=-1.16^0C$

Thus the freezing point of a solution will be $-1.16^0C$

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What inorganic molecule is carbon normally found in?

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It’s CO2

Carbon dioxide

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Answer:

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I don't see any options so there i hope it helps .

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3 years ago

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