It would be measured in newtons :)
Hi Randa, want me to help you with physics? The answer is when the object moves in a straight line.
The amount of work done in emptying the tank by pumping the water over the top edge is 163.01* 10³ ft-lbs.
Given that, the tank is 8 feet across the top and 6 feet high
By the property of similar triangles, 4/6 = r/y
6r = 4y
r = 4/6*y = 2/3*y
Each disc is a circle with area, A = π(2/3*y)² = 4π/9*y²
The weight of each disc is m = ρw* A
m = 62.4* 4π/9*y² = 87.08*y²
The distance pumped is 6-y.
The work done in pumping the tank by pumping the water over the top edge is
W = 87.08 ∫(6-y)y² dy
W = 87.08 ∫(6y³ - y²) dy
W = 87.08 [6y⁴/4 - y³/3]
W = 87.08 [3y⁴/2- y³/3]
The limits are from 0 to 6.
W = 87.08 [3*6⁴/2 - 6³/3] = 87.08* [9*6³ - 2*36] = 87.08(1872) = 163013.76 ft-lbs
The amount of work done in emptying the tank by pumping the water over the top edge is 163013.76 ft-lbs.
To know more about work done:
brainly.com/question/16650139
#SPJ4
PLASTICITY, the MALLEABILITY of the body; extent to which they will absorb water after firing; and SHRINKAGE the extent of revolution in size of a body as water is removed.
There you go!
Answer:
Voltage will be 100 volt
Explanation:
We have given current through the circuit i = 0.1 A
Power dissipated P = 10 W
We know that power dissipated through any resistive cirvuit is given by
, here i is current and R is resistance
So 
R =1000 ohm
Now according to ohm's law V = iR
So Voltage V = 0.1×1000 = 100 volt
