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An iron nail with a mass of 12 grams absorbs 12 Joules of heat. If the nail was initially at 25°C, what is the final temperature

elena-s [515]

The answer to “An iron nail with a mass of 12 g absorbs 15 J of heat. If the nail was initially at 28 °C, what is its final temperature?” is broken down into a number of easy to follow steps, and 27 words. Since the solution to 81P from 3 chapter was answered, more than 4841 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 81P from chapter: 3 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. This full solution covers the following key subjects: nail, iron, heat, initially, final. This expansive textbook survival guide covers 19 chapters, and 2045 solutions.

8 0

3 years ago

Determine the group and the period in which each of the following elements is

kompoz [17]

This element is called Neon and it is part of the group known as Noble gases or group 8 and it is in period 2

5 0

1 year ago

There are ___________ of different kinds of proteins in the human body?

Natasha2012 [34]

Answer:

In humans, up to ten different proteins can be traced to a single gene. Proteome: It is now estimated that the human body contains between 80,000 and 400,000 proteins. However, they aren't all produced by all the body's cells at any given time. Cells have different proteomes depending on their cell type.

Explanation:

7 0

3 years ago

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g You observed the formation of several precipitates in the Reactions in Solution lab exercise. Identify the precipitate in each

RUDIKE [14]

Answer:

For a: Lead iodide is a yellow precipitate.

For b: Barium sulfate is a white precipitate.

For c: Ferric hydroxide is a brown precipitate.

For d: Copper (II) hydroxide is a blue precipitate.

Explanation:

Precipitation reaction is defined as the reaction where a solid precipitate (solid substance) is formed at the end of the reaction. It is insoluble in water.

For the given options:

For (a):

The chemical reaction between KI and lead (II) nitrate follows:

$2KI(aq)+Pb(NO_3)_2(aq)\rightarrow PbI_2(s)+2KNO_3(aq)$

The iodide of lead is generally insoluble in water. Thus, lead iodide is a yellow precipitate.

For b:

The chemical reaction between barium chloride and sulfuric acid follows:

$BaCl_2(aq)+H_2SO_4(aq)\rightarrow BaSO_4(s)+2HCl(aq)$

The sulfate of barium is insoluble in water. Thus, barium sulfate is a white precipitate.

For c:

The chemical reaction between NaOH and ferric chloride follows:

$3NaOH(aq)+FeCl_3(aq)\rightarrow Fe(OH)_3(s)+3NaCl(aq)$

The hydroxide of iron is insoluble in water. Thus, ferric hydroxide is a brown precipitate.

For d:

The chemical reaction between NaOH and copper sulfate follows:

$CuSO_4+2NaOH\rightarrow Cu(OH)_2+Na_2SO_4$

The hydroxide of copper is insoluble in water. Thus, copper (II) hydroxide is a blue precipitate.

6 0

3 years ago

Calculate the pH of the 4M NaOH

krek1111 [17]

$\text{NaOH}(aq) \longrightarrow \text{Na}^{+} (aq)+ \text{OH}^{-}(aq)\\\\k_w = [\text{H}_3 \text{O}^{+}][\text{OH}^{-}]\\\\\implies 10^{-14} = [\text{H}_3 \text{O}^{+}] \cdot 4\\\\\implies [\text{H}_3 \text{O}^{+}] = \dfrac{10^{-14}}4 = 2.5 \times 10^{-15}~ M\\\\\text{pH} = -\log[\text{H}_3 \text{O}^{+}] = -log(2.5 \times 10^{-15})=14.603$

3 0

2 years ago

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