PLEASE HELP DUE IN EXACTLY 15 mins!! i will give you branliest

Which of the following hydrocarbons will most likely be found around cows? ethane methane octane decane

Wewaii [24]

Methane
CH₄
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7 0

3 years ago

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How do the molecules in a liquid behave?

inn [45]

Answer:

in a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.

Explanation:

the attractive forces between particles are strong enough to hold a specific volume but not strong enough to keep the molecules sliding over each other.

7 0

4 years ago

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Someone please help me i dont understand how too do these

sammy [17]

Answer:

0.55

Explanation:

When multiplying values, the number of significant figures in the answer should be the same as the number with the lowest sig figs in the problem which in this case is 2 sig figs (0.17)

3.22 * 0.17 = .5474

Rounded to 2 sig figs = 0.55

6 0

3 years ago

Given a unsorted list of 1024 elements, what is the runtime for linear search if the search key is less than all elements in the

ra1l [238]

Answer:

10

Explanation:

Binary search's runtime is proportional to log (base two) of the number of list elements.

6 0

3 years ago

You had a closed tank of air at a pressure of 4 atm and temperature of 20 degrees Celsius. When the tank and the air are heated

notka56 [123]

Answer:

The pressure will be 4.27 atm.

Explanation:

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Where P = pressure, T = temperature, K = Constant

This law indicates that the quotient between pressure and temperature is constant.

This law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the pressure of the gas increases. And when the temperature is decreased, the pressure of the gas decreases.

You want to study two different states, an initial state and a final state. You have a gas that is at a pressure P1 and a temperature T1 at the beginning of the experiment. By varying the temperature to a new value T2, then the pressure will change to P2, and the following will be fulfilled:

$\frac{P1}{T1} =\frac{P2}{T2}$

In this case:

P1= 4 atm
T1= 20 C= 293 K (being 0 C= 273 K)
P2= ?
T2= 40 C= 313 K

Replacing:

$\frac{4 atm}{293 K} =\frac{P2}{313 K}$

Solving:

$P2= 313 K* \frac{4 atm}{293 K}$

P2= 4.27 atm

<u><em>The pressure will be 4.27 atm.</em></u>

8 0

3 years ago