What is the name of John Daltons theory

What is the percent by volume of 25mL ethanol in 150 mL of water

Virty [35]

The answer would be .166

6 0

3 years ago

How did Bohr solve the contradiction with physics with his model of an atom

daser333 [38]

Answer:

He used Velocity and Radius.

Explanation:

The uncertainty truths contradicts Bohr's thoughts of electrons.

4 0

2 years ago

When 500.0 g of water is decomposed by electrolysis and the yield of hydrogen is only 75.3%, how much hydrogen chloride can be m

Evgen [1.6K]

The amount of hydrogen chloride that can be made is 1064 g

Why?

The two reactions are:

2H₂O → 2H₂ + O₂ 75.3 % yield

H₂ + Cl₂ → 2HCl 69.8% yield

We have to apply a big conversion factor to go from grams of water (The limiting reactant), to grams of HCl, the final product. We have to be very careful with the coefficients and percentage yields!

$500.0gH_2O*\frac{1moleH_2O}{18.01 gH_2O}*\frac{2 moles H_2}{2 moles H_2O}*\frac{2.015g H_2}{1 mole H_2}*\frac{75.3 actual g}{100 theoretical g}=42.12 g H_2$

$42.12H_2*\frac{1 mole H_2}{2.015gH_2}*\frac{2 moles HCl}{1 mole H_2}*\frac{36.46g}{1 mole HCl}*\frac{69.8 actualg}{100 theoreticalg} =1064gHCl$

Have a nice day!

#LearnwithBrainly

7 0

3 years ago

g Suppose 0.0350 g M g is reacted with 10.00 mL of 6 M H C l to produce aqueous magnesium chloride and hydrogen gas. M g ( s ) +

iren2701 [21]

Answer:

Mg will be the limiting reagent.

Explanation:

The balanced reaction is:

Mg + 2 HCl → MgCl₂ + H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Mg: 1 mole
HCl: 2 moles
MgCl₂: 1 mole
H₂: 1 mole

Being the molar mass of each compound:

Mg: 24.3 g/mole
HCl: 36.45 g/mole
MgCl₂: 95.2 g/mole
H₂: 2 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Mg: 1 mole* 24.3 g/mole= 24.3 g
HCl: 2 moles* 36.45 g/mole= 72.9 g
MgCl₂: 1 mole* 95.2 g/mole= 95.2 g
H₂: 1 mole* 2 g/mole= 2 g

0.0350 g of Mg is reacted with 10.00 mL (equal to 0.01 L) of 6 M HCl.

Molarity being the number of moles of solute that are dissolved in a certain volume, expressed as:

$Molarity=\frac{number of moles of solute}{volume}$

in units $\frac{moles}{liter}$

then, the number of moles of HCl that react is:

$6 M=\frac{number of moles of HCl}{0.01 L}$

number of moles of HCl= 6 M*0.01 L

number of moles of HCl= 0.06 moles

Then you can apply the following rule of three: if by stoichiometry 2 moles of HCl react with 24.3 grams of Mg, 0.06 moles of HCl react with how much mass of Mg?

$mass of Mg=\frac{0.06 moles of HCl* 24.3 grams of Mg}{2 moles of HCl}$

mass of Mg= 0.729 grams

But 0.729 grams of Mg are not available, 0.0350 grams are available. Since you have less mass than you need to react with 0.06 moles of HCl, Mg will be the limiting reagent.

7 0

2 years ago

In tne equation below identify the bronsted lowry acid bronsted lowry base conjugate acid conjugate base

Ad libitum [116K]

Answer:

Brønsted-Lowry acid: HNO₂

Brønsted-Lowry base: NH₃

Conjugate acid: NH₄⁺

Conjugate base: NO₂⁻

Explanation:

The equation is:

$HNO_2(aq)+NH_3(aq)\rightarrow NH4^+(aq) + NO2^-(aq)$

Brønsted-Lowry acids are H⁺ donors.

Brønsted-Lowry bases are H⁺ acceptors.

Thus, on the left side, HNO₂ is the acid and NH₃ is the base.

The conjugate acids and conjugate bases are on the right side of the equation.

The conjugate acid is the spieces that is formed after a base accepts the proton; thus it is NH₄⁺. A conjugate acid contains one more H atom and one more + charge than the base that formed it.

The conjugate base is the species that is formed after the acid donates its proton; thus, NO₂⁻ is the conjugate base. A conjugate base contains one less H atom and one more - charge than the acid that formed it.

Summarizing:

Brønsted-Lowry acid: HNO₂

Brønsted-Lowry base: NH₃

Conjugate acid: NH₄⁺

Conjugate base: NO₂⁻

6 0

3 years ago