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PilotLPTM [1.2K]
3 years ago
12

What is the name of John Daltons theory

Chemistry
1 answer:
Rashid [163]3 years ago
5 0

Answer:

It is called the atomic theory I believe.

Explanation:

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What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

4 0
2 years ago
How do you find the IUPAC name for a compound like ZnO
Elden [556K]
To find the IUPAC name for compounds, you must memorize prefixes and suffixes and other terms in determining or naming a compound. The IUPAC name for compound ZnO is Oxozinc or Zinc Oxide. I hope this helps you on your assignment.
6 0
4 years ago
50 g of liquid water is frozen in an ice cube tray. What is the total weight of all of the ice cubes
Fantom [35]
Answer: 50 grams

Explanation: The water is still only going to be 50 grams. Although it’s in a different state, it didn’t gain or lose any water while being frozen.
6 0
2 years ago
How many moles of NH3 can be produced from 15.0 mol of H2 and excess of N2? express your answer numerically in moles
STALIN [3.7K]

Answer:

zhzhsjwuwusysushshsjshshsbshshdhdhshdhdbdbbdf

3 0
4 years ago
The balanced combustion reaction for C 6 H 6 C6H6 is 2 C 6 H 6 ( l ) + 15 O 2 ( g ) ⟶ 12 CO 2 ( g ) + 6 H 2 O ( l ) + 6542 kJ 2C
Lana71 [14]

Explanation:

First, we will calculate the molar mass of C_{6}H_{6} as follows.

Molar mass of C_{6}H_{6} = 6 \times 12 + 6 \times 1

                                   = 78 g/mol

So, when 2 mol of C_{2}H{6} burns, then heat produced = 6542 KJ

Hence, this means that 2 molecules of C_{6}H{6} are equal to 78 \times 2 = 156 g of C_{6}H_{6} burns, heat produced = 6542 KJ

Therefore, heat produced by burning 5.5 g of C_{6}H{6} =                  

       6542 kJ \times \frac{5.5 g}{156 g}

            = 228.97 kJ

            = 228970 J           (as 1 kJ = 1000 J)

It if given that for water, m = 5691 g

And, we know that specific heat capacity of water is 4.186 J/g^{o}C .

As,             Q = m \times C \times (T_{f} - T_{i})

          228970 J = 5691 g \times 4.184 J/g^{o}C \times (T_{f} - 21)
^{o}C

                T_{f} - 21^{o}C = 9.616^{o}C

                T_{f} = 30.6^{o}C

Thus, we can conclude that the final temperature of the water is 30.6^{o}C.

4 0
3 years ago
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