Answer:
Coefficients represents no of moles while subscripts represent no of atoms.
Rip bro but I need the point
LiOH is going to neutralize the acid because it’s a base
Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
1) N = 4,2 moles
M = 24,31 u
m = N x M
= 4.2 x 24.31 = 102.102 kg
2) m = 54.9 grams = 0.0549 kilograms
M (Na) = 22.99 u
N (moles) = m / M
N = 0.0549 / 22.99 = 2.4 x 10^-3 moles
I don’t know if it helped you a bit :)
