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ddd [48]
3 years ago
7

The weight percent of concentrated H2SO4, molar mass=980 g/mol, is 960% and its density is 184 g/ml. What is the molarity of con

centrated H2SO4? 9.79 M 12.0 M 18.0M 532M 245 M avigator AN 20 Backspace HKLIL
Chemistry
1 answer:
Elan Coil [88]3 years ago
8 0

Answer:

<em>C</em> H2SO4 = 9.79 M

Explanation:

  • molarity (M) ≡ # dissolved species / V sln
  • H2SO4 ↔ H3O+  +  SO4-

∴ %w/w H2SO4 = 960% = g H2SO4 / g sln * 100

⇒ 9.6 = g H2SO4 / g sln

calculation base: 1000 g sln

⇒ g H2SO4 = 9600g

⇒<em> </em>mol<em> </em>H2SO4 =<em> </em>9600 g H2SO4 * ( mol H2SO4/ 980g H2SO4 ) = 9.796  mol H2SO4

⇒ V sln = 1000g sln / 1000g/L = 1 L sln

∴ ρ H20 ≅ 1000 Kg/m³ = 1000 g/L

⇒ <em>C</em> H2SO4 = 9.796 mol H2SO4 / 1 L sln

⇒ <em>C</em> H2SO4 = 9.796 M

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Answer:

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Explanation:

Firstly, we need to write a balanced chemical equation.

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Now, we need to know the actual number of moles of hydrogen gas given off.

The number of moles is the mass divided by the atomic mass. The atomic mass of calcium is 40g/mol. The number of moles is thus 0.5/40 = 0.0125 mole

Since the mole ratio is 1:1, the number of moles of hydrogen gas produced too is 0.0125 moles.

We now Proceed to get the mass of the hydrogen gas produced. This is the number of moles of hydrogen multiplied by the molar mass of the diatomic hydrogen gas. The molar mass of the diatomic hydrogen gas is 2g/mol.

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