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Maslowich
3 years ago
9

How loudness of a sound wave depends on the intensity of the sound wave?

Physics
1 answer:
Anestetic [448]3 years ago
3 0
Loudness of a sound wave is directly proportional to the intensity of the sound wave. In other words, when one increases, other also increases and vice-versa

Hope this helps!
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Force has _____. magnitude direction gravity weight
Contact [7]

Answer:

magnitude

Explanation:

7 0
3 years ago
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Why do people put rough strips in their bathtubs?
krok68 [10]

Answer:

hi, the reason is for friction so that they don't fall. subscribe to me on you tube. name is my brainly name

Explanation:

4 0
3 years ago
A metal rod has a moves with a constant velocity of 40 cm/s along two parallel metal rails through a magnetic field of 0.575 T.
love history [14]

Answer:

2.12/R mW

Explanation:

The electrical power, P generated by the rod is

P = B²L²v²/R where B = magnetic field = 0.575 T, L = length of metal rod = separation of metal rails = 20 cm = 0.2 m, v = velocity of metal rod = 40 cm/s = 0.4 m/s and R = resistance of rod = ?

So, the induced emf on the conductor is

E = BLv

= 0.575 T × 0.2 m × 0.4 m/s

= 0.046 V

= 46 mV

The electrical power, P generated by the rod is

P = B²L²v²/R

=  B²L²v²/R

So, P = (0.575 T)² × (0.2 m)² × (0.4 m/s)²

= 0.002116/R W

= 2.12/R mW

3 0
3 years ago
A snowboarder on a slope starts from rest and reaches a speed of 4.2 m/s after 7.3 s
Yakvenalex [24]

The car's acceleration will be 0.575 m/s².The unit of acceleration is m/sec².

<h3>What is acceleration?</h3>

The rate of velocity change concerning time is known as acceleration.

Given data;

Initial velocity, u= 0 m/s

Final velocity, v= 4.2 m/s

Time elapsed, t = 7.3 seconds.

To find ;

Acceleration, a

The acceleration when the change in velocity is observed by the formula as:

a= (v-u)/(t)

Substitute the given values:

a= (4.2-0)/(7.3)

a=(4.2)/(7.3)

a= 0.575 m/s²

Hence, the car's acceleration will be 0.575 m/s².

To learn more about acceleration, refer to the link brainly.com/question/2437624

#SPJ1

3 0
1 year ago
during a typical afternoon thunderstorm in the summer, an area of 66.0 km2 receives 9.57 108 gal of rain in 18 min. how many inc
zheka24 [161]

Answer:

2.16 inch

Explanation:

area under water = 66 km²

= 66 x ( 3280.84 x 12 )² inch²

= 1.023 x 10¹¹ sq inch

volume of rain = 9.57 x 10⁸  gallon = 9.57 x 10⁸ x 231 inch³

= 2.21 x 10¹¹ inch³

If depth of rainfall be t

volume of rain = surface area x depth

= 1.023 x 10¹¹ x t

So ,

1.023 x 10¹¹ x t  = 2.21 x 10¹¹

t = 2.16 inch

5 0
2 years ago
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