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3 years ago

10

a bullet of mass 0.01kg is fired from a gun weighing 5.0 kg. if initial velocity of the bullet is 250m/s. Calculate the velocity

with which the gun recoils.

1 answer:

Nina [5.8K]3 years ago

8 0

Answer:

The formula is MgVg=MbVb.

which is 5×Vg=0.01×250.

5Vg=2.5.

Vg=2.5/5.

Vg=0.5m/s.

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Deneb and the Sun are two stars. Deneb has a diameter that is 109-200 times greater than that of the sun. When seen from earth,

saw5 [17]

I believe it is
B)The Sun is closer than Deneb

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3 years ago

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g

Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:

$k=\sqrt{\frac{I}{M} }$

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration $k=\sqrt{\frac{I}{M} }$

So, moment of rotational inertia (I) of a cylinder about it axis = $\frac{MR^2}{2}$

$k=\sqrt{\frac{\frac{MR^2}{2}}{M} }$

$k=\sqrt{{\frac{MR^2}{2}}* \frac{1}{M} }$

$k=\sqrt{{\frac{R^2}{2}}$

$k={\frac{R}{\sqrt{2}}$

$k={\frac{1.20m}{\sqrt{2}}$

k = 0.8455 m

k ≅ 0.85 m

For the spherical shell of radius

(I) = $\frac{2}{3}MR^2$

$k = \sqrt{\frac{\frac{2}{3}MR^2}{M} }$

$k = \sqrt{\frac{2}{3} R^2}$

$k = \sqrt{\frac{2}{3} }*R$

$k = \sqrt{\frac{2}{3}} *1.20$

k = 0.9797 m

k ≅ 0.98 m

For the solid sphere of radius

(I) = $\frac{2}{5}MR^2$

$k = \sqrt{\frac{\frac{2}{5}MR^2}{M} }$

$k = \sqrt{\frac{2}{5} R^2}$

$k = \sqrt{\frac{2}{5} }*R$

$k = \sqrt{\frac{2}{5}} *1.20$

k = 0.7560

k ≅ 0.76 m

6 0

4 years ago

What is the momentum of an animal with a mass of 72kg who is moving with a velocity of 2.2 m/s

ludmilkaskok [199]

Answer:

The answer is

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Explanation:

The momentum of an object when given it's mass and velocity can be found by using the formula

<h3>momentum = velocity × mass</h3>

From the question

velocity = 2.2 m/s

mass = 72 kg

The momentum is

momentum = 2.2 × 72

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<h3>158.4 kgm/s</h3>

Hope this helps you

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Hi!

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