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3 years ago

10

a bullet of mass 0.01kg is fired from a gun weighing 5.0 kg. if initial velocity of the bullet is 250m/s. Calculate the velocity

with which the gun recoils.

1 answer:

Nina [5.8K]3 years ago

8 0

Answer:

The formula is MgVg=MbVb.

which is 5×Vg=0.01×250.

5Vg=2.5.

Vg=2.5/5.

Vg=0.5m/s.

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stira [4]

Answer:

Explanation:

Given

acceleration is given by

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$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

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at $v=0,\ t=-g$

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$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

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$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

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Colt1911 [192]

Answer:

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Explanation:

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Answer:

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