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Anarel [89]
2 years ago
10

a bullet of mass 0.01kg is fired from a gun weighing 5.0 kg. if initial velocity of the bullet is 250m/s. Calculate the velocity

with which the gun recoils.​
Physics
1 answer:
Nina [5.8K]2 years ago
8 0

Answer:

The formula is MgVg=MbVb.

which is 5×Vg=0.01×250.

5Vg=2.5.

Vg=2.5/5.

Vg=0.5m/s.

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zalisa [80]

Answer:

u(t)=0.78sin12.78t

Explanation:

We are given that

Mass,m=148 g

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We know that

\omega_0=\sqrt{\frac{g}{L}}=\sqrt{\frac{980}{6}}=12.78 rad/s

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u(t)=Acos12.78 t+Bsin 12.78t

u(0)=0

Substitute the value

A=0

u'(t)=-12.78Asin12.78t+12.78 Bcos12.78 t

Substitute u'(0)=10

12.78B=10

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Answer:

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