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3 years ago

Science

Chemistry

1 answer:

NeTakaya3 years ago

8 0

Answer:

I could press down on each lump of clay until it becomes a flat layer. Next, I could stack the layers one on top of the other. Finally, I would have to force the layers to bend into tight folds by pushing and pressing on the clay.

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The charge of single electron

irga5000 [103]

The answer is B.

plz mark me as brainliest. i really need it.

8 0

4 years ago

In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of

Likurg_2 [28]

The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
(HBr) (KOH)

Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M

Concentration of KOH is 0.9756 M.

3 0

3 years ago

Read 2 more answers

MAXImum [283]

Answer:

Sulfuric acid + Zinc = reactant

Zinc sulfate + hydrogen = product

Lead oxide + carbon = reactant

lead + carbondioxide = product

Explanation:

Chemical equation:

Sulfuric acid + Zinc → Zinc sulfate + hydrogen

H₂SO₄ + Zn → ZnSO₄ + H₂

In this reaction sulfuric acid and zinc react to produce the zinc sulfate and hydrogen. That's why sulfuric acid and zinc are reactant. While zinc sulfate and hydrogen are products.

2nd reaction:

Lead oxide + carbon → lead + carbondioxide

2PbO + C → 2Pb + CO₂

In this reaction Lead oxide and carbon react to produce the lead and carbondioxide. That's why Lead oxide and carbon are reactant. While lead and carbondioxide are products.

3 0

3 years ago

How much hear must be obsorberd by 375.0 grams of water to raise its temperature from 10.0c to 35.0c? The specific heat capacity

inysia [295]

Answer:

The heat absorbed by water is 39243.75 J.

Explanation:

Given data:

Mass of water = 375.0 g

Heat absorbed by water= ?

Initial temperature = 10.0°C

Final temperature = 35.0 °C

The specific heat capacity of water = 4.186 j/g.°C

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 35°C - 10°C

ΔT = 25°C

Q = m.c. ΔT

Q = 375.0 g× 4.186 j/g °C × 25°C

Q = 39243.75 J

The heat absorbed by water is 39243.75 J.

3 0

3 years ago

cooling a sample of matter from 70°c to 10°c at constant pressure causes its volume to decrease from 873.6 to 712.6 cm3. classif

jek_recluse [69]

Explanation:

Expression for the coefficient of thermal expansion is as follows.

$\alpha = \frac{1}{V}(\frac{\Delta V}{\Delta T})$

where, V = initial volume

$\Delta V$ = Final volume - initial volume

= (712.6 - 873.6) $cm^{3}$

= -161 $cm^{3}$

Now, we will calculate the change in temperature as follows.

$\Delta T$ = Final temperature - Initial temperature

= (10 + 273) K - (70 + 273) K

= 283 K - 343 K

= -60 K

Substituting these values into the equation as follows.

$\alpha = \frac{1}{873.6} \times (\frac{161}{60}) K^{-1}$

= 0.00307 $K^{-1}$

It is known that for non-ideal gases the value of alpha is 0.366% which is 0.00366 per Kelvin. As it is close to our result, hence the given sample of gas is a non-ideal gas.

3 0

4 years ago