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3 years ago

Which one is the least reactive element is Ar Na СІ Mg

Chemistry

1 answer:

34kurt3 years ago

7 0

Answer:

Explanation:

does not react with anything it has a full electron shell so it does not combine and it is a noble gas

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Starch is considered a biological polymer because it contains repeating units (C6H10O5)n.

evablogger [386]

The answer for the question is true

7 0

3 years ago

Read 2 more answers

When 100.g Mg3N2 reacts with 75.0 g H2O, what is the maximum theoretical yield of NH3?

Temka [501]

Answer : The correct option is, 23.6 g

Explanation : Given,

Mass of $Mg_3N_2$ = 100.0 g

Mass of $H_2O$ = 75.0 g

Molar mass of $Mg_3N_2$ = 101 g/mol

Molar mass of $H_2O$ = 18 g/mol

First we have to calculate the moles of $Mg_3N_2$ and $H_2O$ .

$\text{Moles of }Mg_3N_2=\frac{\text{Given mass }Mg_3N_2}{\text{Molar mass }Mg_3N_2}$

$\text{Moles of }Mg_3N_2=\frac{100.0g}{101g/mol}=0.990mol$

and,

$\text{Moles of }H_2O=\frac{\text{Given mass }H_2O}{\text{Molar mass }H_2O}$

$\text{Moles of }H_2O=\frac{75.0g}{18g/mol}=4.17mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$Mg_3N_2(s)+6H_2O(l)\rightarrow 3Mg(OH)_2(aq)+2NH_3(g)$

From the balanced reaction we conclude that

As, 6 moles of $H_2O$ react with 1 mole of $Mg_3N_2$

So, 4.17 moles of $H_2O$ react with $\frac{4.17}{6}=0.695$ moles of $Mg_3N_2$

From this we conclude that, $Mg_3N_2$ is an excess reagent because the given moles are greater than the required moles and $H_2O$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NH_3$

From the reaction, we conclude that

As, 6 moles of $H_2O$ react to give 2 moles of $NH_3$

So, 4.17 moles of $H_2O$ react to give $\frac{2}{6}\times 4.17=1.39$ mole of $NH_3$

Now we have to calculate the mass of $NH_3$

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

Molar mass of $NH_3$ = 17 g/mole

$\text{ Mass of }NH_3=(1.39moles)\times (17g/mole)=23.6g$

Therefore, the maximum theoretical yield of $NH_3$ is, 23.6 grams.

4 0

3 years ago

When the ideal gas law is arranged as shown below, what property of the gas is being solved for (represented by the X)? x equals

Mkey [24]

That's kind of a ponderous way to describe it, but your 'X' represents
the absolute temperature of the ideal gas.

3 0

3 years ago

How many grams of water when supplied with 348j of heat will gain a temperature of 5.2°c?

Zielflug [23.3K]

We can use the heat equation,

Q = mcΔT

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

In this problem there is no any data about initial temperature of the water. So, we can assume that given temperature of 5.2 °C as the temperature difference.

Q = 348 J

m = ?

c = 4.186 J g⁻¹ °C⁻¹

ΔT = 5.2 °C

By applying the formula,
348 J = m x 4.186 J g⁻¹ °C⁻¹ x 5.2 °C
m = 15.99 g

Hence, the grams of water is 15.99.

8 0

3 years ago

I need help bad bro i have a 30 cs this is missing

Nat2105 [25]

Answer: 11.02 moles of Ag can be formed.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$