A 50 kg astronaut floating in space throws her 2 kg wrench to the left at 10
1 answer:
The astronaut will move at 0.4 m/s in the opposite direction to the wrench
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the astronaut-wrench system must be conserved before and after the launch.
Before the launch, the total momentum is zero, since the astronaut is at rest:
p = 0 (1)
After the launch, the total momentum is:
(2)
where :
m = 2 kg is the mass of the wrench
v = 10 m/s is the velocity of the wrench
M = 50 kg is the mass of the astronaut
V is the recoil velocity of the astronaut
Since momentum is conserved, we can write (1) = (2), and so we can solve for V:
And the negative sign means that the astronaut will move in the opposite direction to the wrench.
Learn more about conservation of momentum:
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Answer:
The sound level of the 26 geese is
Explanation:
From the question we are told that
The sound level is
The number of geese is
Generally the intensity level of sound is mathematically represented as
The intensity of sound level in dB for one goose is mathematically represented as
Where I_o is the threshold level of intensity with value
is the intensity for one goose in
For 26 geese the intensity would be
Then the intensity of 26 geese in dB is
From the law of logarithm we have that