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4 years ago

Which of the following is not an example of kinetic energy being converted to potential energy?

Physics

2 answers:

KengaRu [80]4 years ago

6 0

The list of choices you provided with your question
is utterly devoid of any such examples.

Bumek [7]4 years ago

6 0

You did not give any answers to choose from. So I'll just explain to you what the difference is.

Kinetic energy means the object is in motion, or is moving.

Potential energy means the object is not moving, but it has the potential to.

Example:
You are holding your phone in your hand one foot above the ground and you are not moving it at all (Potential energy). You then drop your phone and it begins to fall (Kinetic energy).

Now, you hold your phone in your hand 6 feet above the ground and you are not moving it at all (More Potential energy). You then drop your phone and it begins to fall.. very very hard... (More Kinetic Energy).

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A train travels 90 kilometers in 1 hours, and then 60 kilometers in 3 hours. What is its average speed

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3 years ago

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3 years ago

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Consider two laboratory carts of different masses but identical kinetic energies and the three following statements. I. The one

kolbaska11 [484]

Answer:

d) I and III only.

Explanation:

Let be $m_{1}$ and $m_{2}$ the masses of the two laboratory carts and let suppose that $m_{1} > m_{2}$ . The expressions for each kinetic energy are, respectively:

$K = \frac{1}{2}\cdot m_{1}\cdot v_{1}^{2}$ and $K = \frac{1}{2}\cdot m_{2}\cdot v_{2}^{2}$ .

After some algebraic manipulation, the following relation is constructed:

$\frac{m_{1}}{m_{2}} = \left(\frac{v_{2}}{v_{1}}\right)^{2}$

Since $\frac{m_{1}}{m_{2}} > 1$ , then $\frac{v_{2}}{v_{1}} > 1$ . That is to say, $v_{1} < v_{2}$ .

The expressions for each linear momentum are, respectively:

$p_{1} = \frac{2\cdot K}{v_{1}} = m_{1}\cdot v_{1}$ and $p_{2} = \frac{2\cdot K}{v_{2}} = m_{2}\cdot v_{2}$

Since $v_{1} < v_{2}$ , then $p_{1} > p_{2}$ . Which proves that statement I is true.

According to the Impulse Theorem, the impulse needed by cart I is greater than impulse needed by cart II, which proves that statement II is false.

According to the Work-Energy Theorem, both carts need the same amount of work to stop them. Which proves that statement III is true.

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3 years ago

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EleoNora [17]

Answer:

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Explanation:

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