Which of the following is not an example of kinetic energy being converted to potential energy?

Physics

2 answers:

KengaRu [80]3 years ago

6 0

The list of choices you provided with your question
is utterly devoid of any such examples.

Bumek [7]3 years ago

6 0

You did not give any answers to choose from. So I'll just explain to you what the difference is.

Kinetic energy means the object is in motion, or is moving.

Potential energy means the object is not moving, but it has the potential to.

Example:
You are holding your phone in your hand one foot above the ground and you are not moving it at all (Potential energy). You then drop your phone and it begins to fall (Kinetic energy).

Now, you hold your phone in your hand 6 feet above the ground and you are not moving it at all (More Potential energy). You then drop your phone and it begins to fall.. very very hard... (More Kinetic Energy).

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Does the mass of a pendulum affects the period of oscillation

pshichka [43]

Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.

8 0

2 years ago

A 0.0450 kg bullet is accelerated from rest to a speed of 425 m/s in a 2.25 kg rifle (which is inititally at rest). The pain of

Mrac [35]

Answer:

If the rifle is held loosely away from the shoulder, the recoil velocity will be of -8.5 m/s, and the kinetic energy the rifle gains will be 81.28 J.

Explanation:

By momentum conservation, and given the bullit and the recoil are in a straight line, the momentum analysis will be unidimentional. As the initial momentum is equal to zero (the masses are at rest), we have that the final momentum equals zero, so

$0=P_{f}=m_{b} *v_{b}+m_{r}*v_{r}$

now we clear $v_{r}$ and use the given data to get that

$v_{r}=-8.5\frac{m}{s}$

But we have to keep in mind that the bullit accelerate from rest to a speed of 425 m/s, then if the rifle were against the shoulder, the recoil velocity would be a fraction of the result obtained, but, as the gun is a few centimeters away from the shoulder, it is assumed that the bullit get to its final velocity, so the kick of the gun, gets to its final velocity $\bold{v_{r}}$ too.