Answer:
61.22m
Explanation:
Maximum height in projectile is expressed as;
H = u²sin²θ/2g
u is the speed
g is the acceleration due to gravity
θ is the angle of projection
Substitute the given values into the formula;
H = u²sin²θ/2g
H = 40²sin²60/2g
H = 1600(0.8660)²/2(9.8)
H = 1600(0.8660)²/2(9.8)
H = 1,199.9/19.6
H = 61.22m
Hence the maximum height achieved by the ball is 61.22m
Answer:
- R = ( 4.831 m , 1.469 m )
- Direction of R relative to the x axis= 16°54'33'
Explanation:
Knowing the magnitude and directions relative to the x axis, we can find the Cartesian representation of the vectors using the formula

where
its the magnitude and θ.
So, for our vectors, we will have:


and


Now, we can take the sum of the vectors




This is R in Cartesian representation, now, to find the magnitude we can use the Pythagorean theorem





To find the direction, we can use




As we are in the first quadrant, this is relative to the x axis.
<span>b. The coefficient of static friction for all contacting surfaces is μs=0.35. neglect friction at the rollers.
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