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Dafna11 [192]
2 years ago
5

If the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide before coming to rest?

Solve this problem using conservation of energy. initial speed is 5.3 m/s
Physics
1 answer:
Gnoma [55]2 years ago
4 0

Hi there!

We know that:

Ei = Ef

There is work being done on the object, so:

W = Force · displacement = F · d ⇒ work due to friction

KEi - Fd = KEf (0)

KEi = Fd

Input variables:

1/2mv² = μmgd

Cancel out the mass:

1/2v² = μgd

Solve for d:

1/2(5.3²)/(0.05 · 9.81) = 28.63 m

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Answer:

the velocity of the bullet-wood system after the collision is 2.48 m/s

Explanation:

Given;

mass of the bullet, m₀ = 20 g = 0.02 kg

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velocity of the wood, v₁ = 0

Let the velocity of the bullet-wood system after collision = v

Apply the principle of conservation of linear momentum to calculate the final velocity of the system;

Initial momentum = final momentum

m₀v₀ + m₁v₁ = v(m₀ + m₁)

0.02 x 250  + 2 x 0    =    v(2  + 0.02)

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Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s

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