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Dafna11 [192]
2 years ago
5

If the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide before coming to rest?

Solve this problem using conservation of energy. initial speed is 5.3 m/s
Physics
1 answer:
Gnoma [55]2 years ago
4 0

Hi there!

We know that:

Ei = Ef

There is work being done on the object, so:

W = Force · displacement = F · d ⇒ work due to friction

KEi - Fd = KEf (0)

KEi = Fd

Input variables:

1/2mv² = μmgd

Cancel out the mass:

1/2v² = μgd

Solve for d:

1/2(5.3²)/(0.05 · 9.81) = 28.63 m

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A tuning fork labeled 392 Hz has the tip of each of its two prongsvibrating with an amplitude of 0.600mma) What is the maximum s
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The tuning fork is moving by simple harmonic motion: so, the maximum speed of the tip of the prong is related to the frequency and the amplitude by

v_{max}=\omega A

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v_{max} is the maximum speed

\omega is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

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b)  3.0\cdot 10^{-5} J

The fly's maximum kinetic energy is given by

K=\frac{1}{2}mv_{max}^2

where

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v_{max}=1.48 m/s is the maximum speed

Substituting into the equation, we find

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7 0
3 years ago
A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected
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The ball's initial kinetic energy

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A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected downward at A with the launch speed v0. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A? Ignore friction and air resistance.

From conservation of energy which states that energy can neither be created nor be destroyed, but can be transformed from one form to another.

Ki+Ui=Kf+Uf

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Ui=initial potential energy

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we know that \frac{1}{2} mu^{2} +mgha=\frac{1}{2} mv^{2} +mghb

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ha=downward height a

hb=upward height b

u=initial velocity u

v=final velocity v, which is 0

g=acceleration due to gravity

v=0 at final velocity

1/2mu^2+mgha=0+1/2mv^2

ha=hb+Ki/mh

From the above equation, we can conclude that the ball's initial kinetic energy  is responsible for making the ball reach point B.

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Answer:

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