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Dafna11 [192]
2 years ago
5

If the coefficient of kinetic friction between the puck and the ice is 0.05, how far does the puck slide before coming to rest?

Solve this problem using conservation of energy. initial speed is 5.3 m/s
Physics
1 answer:
Gnoma [55]2 years ago
4 0

Hi there!

We know that:

Ei = Ef

There is work being done on the object, so:

W = Force · displacement = F · d ⇒ work due to friction

KEi - Fd = KEf (0)

KEi = Fd

Input variables:

1/2mv² = μmgd

Cancel out the mass:

1/2v² = μgd

Solve for d:

1/2(5.3²)/(0.05 · 9.81) = 28.63 m

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A 5.0-μC charge is placed at the 0 cm mark of a meter stick and a -4.0 μC charge is placed at the 50 cm mark. At what point on a
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Answer:

The distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

Explanation:

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q₁ = 5 μ C

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d= 50 cm

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K\dfrac{5\ \mu}{x^2}=K\dfrac{4\mu }{(50-x)^2}\\\\\dfrac{5}{x^2}=\dfrac{4 }{(50-x)^2}\\\\\\5(50-x)^2=4x^2\\(50-x)^2=0.8x^2\\\\50-x =0.89x\\\ x=\dfrac{50}{1.89}\ cm\\\\\\x=26.45\ cm\\

Therefore the distance from charge 5 μ C = 26.45 cm and the distance from - 4 μ C is 23.55 cm.

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