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2 years ago

Jen is conducting an experiment involving a device known as a pith-ball electroscope, shown below.

Physics

2 answers:

Serggg [28]2 years ago

7 0

Answer:

bring each tube close to the plastic ball and note any movement of the ball

Explanation:

Electric fields can exert forces on objects, even if the objects involved are not touching. One way to demonstrate that electric fields exist around charged objects is to observe the effects of their forces at a distance.

Since the plastic ball of the electroscope is made of insulating plastic and is uncharged, it will be attracted to any charged object brought near it. So Jen can observe the effects of the tube's electric fields by bringing each tube close to the plastic ball and noting any movement of the ball. If the ball moves toward a tube, then the process that Jen used on the tube generated an electric field.

andreev551 [17]2 years ago

6 0

Answer:

bring each tube close to the plastic ball and note any movement of the ball

Explanation:

study island

just took the test!!!!!

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A 13 kg hanging sculpture is suspended by a 95-cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at its fundame

Artyom0805 [142]

Answer:

$f=81.96 \ Hz$

Explanation:

Givens

$L=95cm$

$m_{sculpture} =13kg$

$m_{wire}=5g$

The frequency is defined by

$f=\frac{v}{\lambda}$

Where $v$ is the speed of the wave in the string and $\lambda$ is its wave length.

The wave length is defined as $\lambda = 2L = 2(0.95m)=1.9m$

Now, to find the speed, we need the tension of the wire and its linear mass density

$v=\sqrt{\frac{T}{\mu} }$

Where $\mu=\frac{0.005kg}{0.95m}= 5.26 \times 10^{-3}$ and the tension is defined as $T=m_{sculpture} g=13kg(9.81 m/s^{2} )=127.53N$

Replacing this value, the speed is

$v=\sqrt{\frac{127.53N}{5.26 \times 10^{-3} } }=155.71 m/s$

Then, we replace the speed and the wave length in the first equation

$f=\frac{v}{\lambda}\\f=\frac{155.71 m/s}{1.9m}\\ f=81.96Hz$

Therefore, the frequency is $f=81.96 \ Hz$

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OverLord2011 [107]

I think the correct answer from the choices would be that metals donate electrons to nonmetals. Ionic bonding involves transfer of valence electrons. The metal looses its valence electrons which makes it a cation while the nonmetal accepts these electrons.

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Answer:

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Answer:

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