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anyanavicka [17]
2 years ago
7

Jen is conducting an experiment involving a device known as a pith-ball electroscope, shown below.

Physics
2 answers:
Serggg [28]2 years ago
7 0

Answer:

bring each tube close to the plastic ball and note any movement of the ball

Explanation:

Electric fields can exert forces on objects, even if the objects involved are not touching. One way to demonstrate that electric fields exist around charged objects is to observe the effects of their forces at a distance.

Since the plastic ball of the electroscope is made of insulating plastic and is uncharged, it will be attracted to any charged object brought near it. So Jen can observe the effects of the tube's electric fields by bringing each tube close to the plastic ball and noting any movement of the ball. If the ball moves toward a tube, then the process that Jen used on the tube generated an electric field.

andreev551 [17]2 years ago
6 0

Answer:

bring each tube close to the plastic ball and note any movement of the ball

Explanation:

study island

just took the test!!!!!

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A ball is dropped and falls with an acceleration of 9.8 m/s2 downward. It hits the ground with a velocity of 49 m/s downward. Ho
il63 [147K]
Hey!

NOTE-:

u= initial velocity
v= final velocity
g= acceleration due to gravity
t= time

u= 0
v= 49 m/s
t=?
g= 9.8 m/s^2

Using first equation of motion -

v-u=at
49-0= 9.8×t
49 = 9.8t
49/9.8= t
t= 5 second


Hope it helps...!!!
6 0
3 years ago
A car accelerates from rest at a constant rate of 2m/s2 for 5s. what is the speed of a car at the end of that time?
Fiesta28 [93]
Good afternoon.


We have:

\mathsf{V_0 = 0}\\ \mathsf{a = 2 \ m/s^2}\\ \mathsf{t = 5 \ s}

The function of velocity:

\mathsf{V = V_0+at}\\ \\ \mathsf{V = 0 + 2t}\\ \\ \mathsf{V = 2t}


For t = 5 s:

\mathsf{V = 2\cdot 5}\\ \\ \boxed{\mathsf{V = 10 \ m/s}}
4 0
3 years ago
Solve the inequality 2(n+3) – 4&lt;6. Then graph<br> the solution.
Aloiza [94]
The solution is 22 2(n+3)-4&6
6 0
3 years ago
Can i get help for the parts for the two questions? MATHPHYSSSS
Anestetic [448]

Explanation:

003 (part 1 of 2)

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P = F / A

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P = 229,320 Pa

003 (part 2 of 2)

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P = 229,320 Pa × (1 psi / 6895 Pa)

P = 33.3 psi

004 (part 1 of 2)

Since the collisions are elastic, the angle of reflection is the same as the angle of incidence (it bounces off at the same angle).

Impulse = change in momentum

F Δt = m Δv

F (36 s) = (300 × 0.003 kg) (5.2 sin 57° m/s − (-5.2 sin 57° m/s))

F = 0.218 N

004 (part 2 of 2)

Pressure is force over area.

P = F / A

P = 0.218 N / 0.712 m²

P = 0.306 N/m²

7 0
3 years ago
3. How do you represent the strength of a<br> force in a free-body diagram?
ivann1987 [24]
Generally, the length of the line will indicate how strong the force is. If you have two opposing forces and one is higher than the other, you would draw the line of the higher force visibly longer.
3 0
3 years ago
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