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elena-14-01-66 [18.8K]
3 years ago
9

A surface will be an equipotential surface if (there may be more than one correct choice).A. the electric field is zero at all p

oints on it.B. the electric field is tangent to the surface at all points.C. the electric field is perpendicular to the surface at all points.a. Ab. A, Bc. A, Cd. C
Physics
1 answer:
aev [14]3 years ago
6 0

Answer:

c. A, C

Explanation:

On equi-potential surface, fields are equal in magnitude at all points . If field is zero at all points , they will be equal so first option is correct.

Field is perpendicular to  equipotential surface at all points.

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A small block with mass 0.0400 kg is moving in the xy-plane. The net force on the block is described by the potentialenergy func
OlgaM077 [116]

Answer:

A= 148.92  m/s²

Explanation:

Given that

U(x,y) = (6.00  )x²  - (3.75  )y ³

m= 0.04 kg

Now force in the x-direction

Fx= - dU/dx

U(x,y) = (6.00  )x²  - (3.75  )y ³

dU/dx= 12 x

When x=0.4 m

dU/dx= 12 x 0.4 = 4.8

So we can say that

Fx= - 4.8 N

From Newtons law

F= m a

- 4.8 = 0.04 x a

a = -120 m/s²

Acceleration in x direction ,a = -120 m/s²

In y -direction

F= - dU/dy

U(x,y) = (6.00  )x²  - (3.75  )y ³

dU/dy = 0 - 3.75 x 3 y²

When y = 0.56 m

dU/dy = - 3.75 x 3 x 0.56 x 0.56

dU/dy = - 3.52

So we can say that force in y -direction

F= 3.52 N

F= m a'

3.52 = 0.04 x a'

a'=88.2 m/s²

acceleration in y direction is 88.2 m/s²

The resultant acceleration

A=\sqrt{a^2+a'^2}

A=\sqrt{120^2+88.2^2}

A= 148.92  m/s²

7 0
3 years ago
in a one dimensional collision, a 4kg object and 6 kg onject have initial velocity. calculate the magnitude of impulse
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in a one dimensional collision, a 4kg object with 5ms^1 and 6 kg object with 2ms^1 have initial velocity, the magnitude of impulse is 12 , 18

given,

mass 1 = 4kg

mass 2 = 6kg

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velocity 2 = 2ms^1

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Impulse 2 = 6*(5-2)

= 18

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8 0
1 year ago
The flow control circuit design that can best control an overrunning load is the ____ circuit.
lara31 [8.8K]

The meter out circuit is the flow control circuit design that can most effectively control an overrunning load.

The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.

<h3>What is a Circuit ?</h3>

In electronics, a circuit is a complete circular conduit through which electricity flows. A simple circuit consists of conductors, a load, and a current source. The term "circuit" broadly refers to any continuous path via which electricity, data, or a signal might flow.

  • The directional valve shifts, causing the actuator to move faster than pump flow can fill it due to an overrunning load. Oil is leaking from one side, whereas there is none on the other.

Hence, flow control circuit design that can best control an overrunning load is the opposing circuit

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What major region does this profile<br> most likely represent?
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Answer:

A mid ocean ridge possibly a plate margin spreading area

Explanation:

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A force is a push or pull upon an object resulting from the object's interaction with another object.

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