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madreJ [45]
3 years ago
14

True or False Criminals structure crime. For instance, crack cocaine street dealers prefer the middle of a long block as the bes

t location for dealing.
Physics
1 answer:
LenaWriter [7]3 years ago
8 0
True. Though typically crack deals take place in a car, or in an alley. The middle of a long block is kind of exposed. It could happen anywhere in Chicago though.
But yeah, criminals structure crime.
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A 70 kg man's arm, including the hand, can be modeled as BIO 75-cm-long uniform rod with a mass of 3.5 kg. When the man raises b
Butoxors [25]

Answer:

  Δy = 7.1 cm

Explanation:

The center of mass of a body is defined

            y_{cm} = 1 /M ∑m_{i}  y_{i}i

Where M is the total mass of the body, m mass of each part and ‘y’ height

Let's apply this equation to our case

We locate the reference system on the shoulders

The height of the arms is at its midpoint

            y = -75/2 = 37.5 cm

With arms down

            y_{cm} = 1/70 (63 y₀ - 3.5 37.5 - 3.5 37.5)

            y_{cm} = 1/70 (63 y)₀ - 7 37.5)

With arms up

          y_{cm}’= 1/70 (63 y₀ + 3.5 y + 3.5 y)

          y_{cm}’= 1/70 (63y₀ + 7 35.5)

let's subtract the two equations

        y_{cm}’ - y_{cm} = 1/70 2 (7 35.5)

         Δy = y_{cm}’ - y_{cm} = 2 7 35.5 / 70

         ΔY = 7.1 cm

7 0
2 years ago
A 50N girl pushes a 10,000 N car with force of 200N. What is the force the car pushes back at the girl? *
miss Akunina [59]

Answer:

200N

Explanation:

EVERY FORCE IS OPPOSED BY AN EQUAL FORCE, REGARDLESS OF THE WEIGHT OF THE OBJECTS APPLYING THE FORCE.

8 0
2 years ago
After the first few seconds of a race, a runner runs at the same speed until she approaches the finish line, at which point she
Rzqust [24]

DUJFIOflmC VANWSER

EXPLANTATION

5 0
2 years ago
Speed is usually what
kolbaska11 [484]

Answer:

measured in GHz?

Explanation:

im not sure what the context is it depends on what your lesson is on

3 0
3 years ago
a hawk flies in a horizontal arc of radius 10.3 m at a constant speed of 4.8 m/s. find its centripetal acceleration. answer in u
n200080 [17]

The hawk’s centripetal acceleration is 2.23 m/s²

The magnitude of the acceleration under new conditions is 2.316 m/s²

radius of the horizontal arc = 10.3 m

the initial constant speed = 4.8 m/s

we know that the centripetal acceleration is given by

    a_{c}  = \frac{v^{2} }{r}

   a_{c}  = 23.04/10.3

    a_{c}  = 2.23 m/s²

It continues to fly but now with some tangential acceleration

a_{t} = 0.63 m/s²

therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration

so

a_{net}  =  \sqrt{a_{c} ^{2} +a_{t} ^{2}   }

a_{net}  =  \sqrt{4.97 + 0.396}

a_{net}  =  2.316 m/s²

So the magnitude of  net acceleration will become 2.316 m/s².

learn more about acceleration here :

brainly.com/question/11560829

#SPJ4

8 0
1 year ago
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