Question

A cell phone weighing 80 grams is flying through the air at 15 m/s what is the kinetic energy

Answer 1

Answer:

$9\:\mathrm{J}$

Explanation:

Kinetic energy is given by the following equation:

$KE=\frac{1}{2}mv^2$, where $m$ is mass in $\mathrm{kg}$ and $v$ is velocity in $\mathrm{m/s}$.

Since the cell phone's mass is given in grams, we need to convert this into kilograms:

$80\:\mathrm{g}\cdot \frac{1\:\mathrm{kg}}{1000\:\mathrm{g}}=0.08\:\mathrm{kg}$.

Therefore, the kinetic energy of the cell phone is:

$KE=\frac{1}{2}\cdot 0.08\cdot 15^2=\fbox{ 9\:\mathrm{J} }$.