You put electricity<span> into it at one end and an </span>axle<span> (metal rod) rotates at the other end giving you the power to drive a machine of some kind.
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Answer:![u=\frac{v}{2}\sqrt{5-4sin\phi }](https://tex.z-dn.net/?f=u%3D%5Cfrac%7Bv%7D%7B2%7D%5Csqrt%7B5-4sin%5Cphi%20%7D)
Explanation:
Given
Both cars mass is m
and solving problem in Vertical and horizontal direction
considering + y and +x to be positive and u be the final velocity of system
Conserving Momentum in Vertical direction
![m(2v)+m(-vsin\phi )=2m(ucos\theta )](https://tex.z-dn.net/?f=m%282v%29%2Bm%28-vsin%5Cphi%20%29%3D2m%28ucos%5Ctheta%20%29)
------1
Conserving momentum in x direction
-----2
squaring and adding 1 &2
![(2u)^2=(2v-vsin\phi )^2+(vcos\phi )^2](https://tex.z-dn.net/?f=%282u%29%5E2%3D%282v-vsin%5Cphi%20%29%5E2%2B%28vcos%5Cphi%20%29%5E2)
![4u^2=4v^2+v^2-4v^2sin\phi](https://tex.z-dn.net/?f=4u%5E2%3D4v%5E2%2Bv%5E2-4v%5E2sin%5Cphi%20)
![4u^2=5v^2-4v^2sin\phi](https://tex.z-dn.net/?f=4u%5E2%3D5v%5E2-4v%5E2sin%5Cphi%20)
![u=\frac{v}{2}\sqrt{5-4sin\phi }](https://tex.z-dn.net/?f=u%3D%5Cfrac%7Bv%7D%7B2%7D%5Csqrt%7B5-4sin%5Cphi%20%7D)
It is weight, if I understand your question.
Answer:
if the object is not in motion
Explanation: