3 years ago

How many moles are in 5.34 x 10*21 particles of Nitrogen?

1 answer:

4 0

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ln (88/ 39) = DeltaH / 8.314 (1 / 318 - 1 / 298)

0.814 = DeltaH / 8.314 (2.11 X 10^-4 )

DeltaH = -32.07 kJ

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