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Answer
The empirical formula is CrO₂Cl₂
Explanation:
Empirical formula is the simplest whole number ratio of an atom present in a compound.
The compound contain, Chromium=33.6%
Chlorine=45.8%
Oxygen=20.6%
And the molar mass of Chromium(Cr)=51.996 g mol.
Chlorine containing molar mass (Cl)= 35.45 g mol.
Oxygen containing molar mass (O)=15.999 g mol.
Step-1
Then,we will get,
Cr=
mol
Cl=
mol.
O=
mol.
Step-2
Divide the mole value with the smallest number of mole, we will get,
Cr=
![\frac{0.64}{0.64} =1](https://tex.z-dn.net/?f=%5Cfrac%7B0.64%7D%7B0.64%7D%20%3D1)
Cl=
![\frac{1.29}{0.64} =2](https://tex.z-dn.net/?f=%5Cfrac%7B1.29%7D%7B0.64%7D%20%3D2)
O=
![\frac{1.28}{0.64} =2](https://tex.z-dn.net/?f=%5Cfrac%7B1.28%7D%7B0.64%7D%20%3D2)
Then, the empirical formula of the compound is CrO₂Cl₂ (Chromyl chloride)
The pressure would increase. When the temperature change form cold to hot, the gas will find ways to escape from containment. Thus, if it cannot escape that pressure will keep on increasing as the temperature rises.
The easiest way is to use the Law of Gay-Lussac. This law states that there is a direct relation between the temperature in Kelvin of a gas and the pressure.
Then, namig p the pressure and T the temperature in Kelvin and using subscripts for every state:
p/T is constant ==> p_1 / T_1 = p_2/T_2
From which you obtain:
p_2 = [p_1 / T_1] * T_2
T_1 = 33.0 + 273.15 = 306.15 K
T _2 = 21.4 + 273.15 = 294.55 K
p_1 = 1014 kPa
p_2 = 1014 kPa * 294.55 K / 306.15 K = 975.6 kPa