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nataly862011 [7]
3 years ago
5

A mylar balloon is filled with helium gas to a pressure of 107 kPa when the temperature is 22°C. If the temperature changes to 4

5°C, what will be the pressure of the helium in the balloon?
Chemistry
1 answer:
brilliants [131]3 years ago
5 0

Answer:

Explanation:

To solve this problem, we have to remember the ideal gas theory. We going to use the Gay Lussac Law.

The equation is:

PiTo = PoTi

Where:

<em>Pi =initial pressure</em>

<em>Po = final pressure</em>

<em>Ti = initial temperature</em>

<em>To = final temperature</em>

Let's use this equation and replace the values:

<em>Pi = 107 kPa</em>

<em>Ti = 22°C</em>

<em>To = 45 °C </em>

<em>Po = ? </em>

<em />

You can use the units as the problem gave you.

Using the Gay Lussac law:

107 kPa x 45 °C = Po x 22°C

Po = (4,815 kPa°C / 22°C) = 218.86 kPa

Po = 218 kPa

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