Question

A mylar balloon is filled with helium gas to a pressure of 107 kPa when the temperature is 22°C. If the temperature changes to 45°C, what will be the pressure of the helium in the balloon?

Answer 1

Answer:

Explanation:

To solve this problem, we have to remember the ideal gas theory. We going to use the Gay Lussac Law.

The equation is:

PiTo = PoTi

Where:

Pi =initial pressure

Po = final pressure

Ti = initial temperature

To = final temperature

Let's use this equation and replace the values:

Pi = 107 kPa

Ti = 22°C

To = 45 °C

Po = ?

You can use the units as the problem gave you.

Using the Gay Lussac law:

107 kPa x 45 °C = Po x 22°C

Po = (4,815 kPa°C / 22°C) = 218.86 kPa

Po = 218 kPa