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2 years ago

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vichka [17]2 years ago

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In at least three sentences, explain three disadvantages associated with hydrogen fuel use.

Dmitry_Shevchenko [17]

Here are some disadvantages, is that nitrogen dioxide is a toxic gas and it can still be harmful when ingested by human, also critics of hydrogen fuel cells argue that although these cells do not emit carbon after burning, they give out nitrogen dioxide and other emissions.

Hope this helps

7 0

3 years ago

Que materias o asignaturas disciplinarias consideras que están

zalisa [80]

Las áreas temáticas que pueden estar involucradas en el cuidado del agua son;

Biología

Química

Geología

oceanografía

Geografía

Conservar y compartir es una parte integral de la ciencia ambiental. La ciencia ambiental en sí misma es multidisciplinaria.

Varias áreas temáticas deben estar involucradas en la conservación del medio ambiente.

Estas áreas temáticas incluyen;

Biología

Química

Geología

oceanografía

Geografía

Aprende más: brainly.com/question/10929764

5 0

2 years ago

What is the property of a neutron?

UNO [17]

Answer:

A) 0 charge

Explanation:

neutron=neutral

7 0

3 years ago

If I initially have a gas at a pressure of 12 atm, volume of 23 liters, and temperature of 200 K, and then I raise the pressure

CaHeK987 [17]

Answer : The volume of gas will be 29.6 L

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 12 atm

$P_2$ = final pressure of gas = 14 atm

$V_1$ = initial volume of gas = 23 L

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = 200K

$T_2$ = final temperature of gas = 300K

Now put all the given values in the above equation, we get the final pressure of gas.

$\frac{12atm\times 23L}{200K}=\frac{14\times V_2}{300K}$

$V_2=29.6L$

Therefore, the new volume of gas will be 29.6 L

5 0

2 years ago

Read 2 more answers

What is the total number of calories of heat energy absorbed when 10 grams of water is vaporized at its normal boiling point

Darya [45]

<u>Answer:</u> The amount of energy absorbed by water is 5390 Calories

<u>Explanation:</u>

To calculate the amount of heat absorbed at normal boiling point, we use the equation:

$q=m\times L_{vap}$

where,

q = amount of heat absorbed = ?

m = mass of water = 10 grams

$L_{vap}$ = latent heat of vaporization = 539 Cal/g

Putting values in above equation, we get:

$q=10g\times 539Cal/g=5390Cal$

Hence, the amount of energy absorbed by water is 5390 Calories

6 0

3 years ago