Answer:
103.2 g of AgCl can be made in the reaction
Explanation:
We state the reaction to analyse the problem:
AlCl₃ + 3AgNO₃ → 3AgCl + Al(NO₃)₃
We convert the mass of chloride to moles:
32 g . 1mol/ 133.34g = 0.240 moles
Ratio is 1:3. See the stoichiometry
1 mol of aluminum chloride can produce 3 moles of AgCl
Then, 0.240 will produce (0.240 . 3)/1= 0.720 moles.
We convert the moles to mass: 0.720 mol . 143.32g/1mol = 103.2 g
Is correct hope this helps i have done this before
It is in a large elliptical shape!
Answer:
17.2 moles of Iron are required
Explanation:
Based on the chemical reaction:
2Fe + 3S → Fe₂S₃
<em>2 moles of Fe react with 3 moles of S to produce 1 mole of Iron (III) sulfide</em>
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Assuming and excess of sulfur, if we want to obtain 8.6 moles of Fe₂S₃ are required:
8.6 moles Fe₂S₃ * (2 moles Fe / 1mol Fe₂S₃) =
<h3>17.2 moles of Iron are required</h3>
hope it helps to everyone
