What is the answer???

Chemistry

1 answer:

igomit [66]3 years ago

7 0

The bowl has more volume, the bearing has more volume. The mass is bigger for the bearing because it is heavier than the bowl. It is made of metal and the weight of it is greater than the bowl.(the body shape).

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Janet runs 6.4 miles in one hour. Is it speed or velocity or acceleration

Murrr4er [49]

Answer:

acceleration

Explanation:

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2 years ago

If a tractor trailer and a car are both traveling 50km/h when they hit which will have the greatest change in speed and directio

den301095 [7]

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4 0

2 years ago

For the reaction shown, calculate how many moles of NO2 form when each amount of reactant completely reacts.

Anton [14]

Answer:- 2.4 mol $NO_2$ .

Solution:- It asks to calculate the moles of $NO_2$ formed when 1.2 moles of $N_2O_5$ are reacted.

There is 2:4 mol ratio between $N_2O_5$ and $NO_2$ . So, the moles of reactant are multiplied by the mol ratio to get the moles of $NO_2$ . The calculations are shown below:

$1.2mol N_2O_5(\frac{4mol NO_2}{2mol N_2O_5})$

= 2.4 mol $NO_2$

So, 2.4 moles of $NO_2$ are formed when 1.2 moles of $N_2O_5$ were reacted.

7 0

3 years ago

Read 2 more answers

A substance with a high [H ] would likely have which additional characteristics? a high [OHĂ˘â‚¬"" ] and a high pOH a low [OHĂ˘â

viktelen [127]

The negative log function that determines the acidity or alkalinity by hydronium ion concentration is called pH.

The substance having high $\rm [H]$ will have:

Option B. A low $\rm [OH ^{-}]$ and a high $\rm pOH$

This characteristic can be explained as:

The concentrations of $\rm [H^{+}]$ and $\rm [OH ^{-}]$ are inversely dependent on each other so when the concentration of raises then the concentration of $\rm [OH ^{-}]$ drops and vice versa.

The pH of a solution or substance is calculated with the help of:

$\rm pH = \rm - log \rm [H^{+}]$

From the formula, it can be deduced that when the concentration of $\rm [H^{+}]$ is high then the pH has a low value and it means that the solution is acidic.