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Lostsunrise [7]
3 years ago
7

make a sentence using the terms yoga,Flexibility hatha yoga Namaste sun salutation meditation and relaxation

Physics
1 answer:
Leya [2.2K]3 years ago
3 0

Answer:

Shake and move your body to release stress and shift your energy. Calm your nervous system with breathing exercises, and learn to settle your mind with meditation.

We recommend that you start with the movement classes and then add the breathing and meditation classes directly after, or as a separate practice later in the day or when needed.

Come back to the classes that you found most helpful. You might feel the difference immediately but aim to practice at least 2 classes a week over 3-4 weeks for the most effective results.

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Describe what happens when the rock on the top of a hill is pushed.
Zigmanuir [339]

Answer:

The precise point is that gravitational energy is potential energy unless it makes something move, and then the energy is converted to kinetic energy, no work can be done. So a big rock at the top of a hill has no kinetic energy. Its only when it rolls down that work is done, and this can be converted to useful energy.

Explanation:

6 0
3 years ago
1. A rock of granite has a mass of 50 kg. if it’s weight in water
igor_vitrenko [27]

Answer:

The first part of the question is asking about BUOYANT FORCE or UPTHRUST.

Upthrust =TRUE WEIGHT-APPARENT WEIGHT

TRUE WEIGHT=mg

TRUE weight=50kg×10m/s²

=500N

upthrust=500N-380N

FB=120N

volume of the rock=mass/density.

since the granite is completely submerged, the volume of the displaced liquid will be equal to the volume of the body.

upthrust=Vdg

120N=V×1000kg/m³×10m/s²

120N=V×10000kg/m²s²

120/10000=V

v=0.012m³

please mark brainliest, hope it helped

6 0
3 years ago
How much work does a student (m = 60 kg) do when he Climb a tower 80 m high?
gtnhenbr [62]

Answer:

W = 47040  J

Explanation:

Given that,

The mass of a student, m = 60 kg

Height of the tower, h = 80 m

We need to find the work done in climbing the tower. The work done is given by :

W = mgh

So,

W = 60 × 9.8 × 80

W = 47040  J

So, the required work done is 47040  J.

7 0
3 years ago
a 10. kg ball thrown into the air. it is going 3.0 m/s when thrown. how much potential energy will it have at the top?
Sever21 [200]

Answer:

45 j

Explanation:

At the top, the KE will have been converted to PE

KE = 1/2 mv^2 =PEat-top = 1/2 10 *3^9 = 45 j

6 0
2 years ago
Jenny is sitting on a sled on the side of a hill inclined at 15°. What force is required to keep the sled from sliding down the
WINSTONCH [101]

Answer:

504 N

Explanation:

The force that starts the sled to slide down is:

F = mg sin Ф = 90lb * 9.81m/s² * sin 15° = 198.4kg * 9.81m/s² * sin 15°

7 0
4 years ago
Read 2 more answers
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