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slamgirl [31]
3 years ago
7

A bearing is to be used as shaft support to carry both radial and thrust forces. Calculations show that a 02 series ball bearing

with a bore size of 20 mm would work well for this application. What are the static and dynamic load ratings of this bearing in kN
Engineering
1 answer:
shepuryov [24]3 years ago
4 0

Answer:

The correct answer is "20.8 kN" and "31 kN". A further explanation is given below.

Explanation:

  • The angular touch bearing seems to be a fine replacement while accommodating radial and even some displacement pressures.
  • You may receive static as well as dynamic scores from either the manufacturer's collections.  

The load ratings should be for the SKF bearing including its predetermined distance:

Static load

= 20.8 kN

Dynamic load

= 31 kN

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Viefleur [7K]

Answer:

Both come from the sun

Both are reusable sources

and both don't cause pollution

Explanation:

3 0
2 years ago
Please calculate the current for the circuit below
Aleks04 [339]

Answer:

The answer is "I = 0.0085106383 \ A"

Explanation:

Given:

R= 470  \ \Omega \\\\V= 4 \ v

Formula:

\to V=IR\\\\\to I = \frac{V}{R}\\\\

      = \frac{4}{470}\\\\ = 0.0085106383 \ A

3 0
3 years ago
A(n) ____________________ measures the resistance to current flow in a circuit.
yulyashka [42]

Answer: OHMMETER & MEGOHMMETER:

Explanation: The ohmmeter measures circuit resistance; the megohmmeter measures the high resistance of insulation. A meter used to measure electric current. It is connected as part of a circuit.

6 0
3 years ago
The magic square is an arrangement of numbers in a square grid in such a way that the sum of the numbers in each row, and in eac
Yuki888 [10]

Answer:

See the explanation for the answer;

Explanation:

Matlab code is as given below

-------------------------------------------------------------------------------------Start of code

% Program to create a magic square and verify it

clc

M= magic(5)

% To find sum of elements of each row

r1= sum(M(1,:))      % Sum of row 1

r2= sum(M(2,:))      % Sum of row 2

r3= sum(M(3,:))      % Sum of row 3

r4= sum(M(4,:))      % Sum of row 4

r5= sum(M(5,:))      % Sum of row 5

% To find sum of each coloumn

c1= sum(M(:,1))      % Sum of coloumn 1

c2= sum(M(:,2))      % Sum of coloumn 2

c2= sum(M(:,3))      % Sum of coloumn 3

c2= sum(M(:,4))      % Sum of coloumn 4

c2= sum(M(:,5))      % Sum of coloumn 5

% To find sum of diagonal

d1= sum(diag(M))               % Sum of principal diagonal elements

d2= sum(diag(fliplr(M)))      

-------------------------------------------------------------------------------End of code

Following results are obtained when executed.

M =

   17    24     1     8    15

   23     5     7    14    16

    4     6    13    20    22

   10    12    19    21     3

   11    18    25     2     9

r1 =

   65

r2 =

   65

r3 =

   65

r4 =

   65

r5 =

   65

c1 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

c2 =

   65

d1 =

   65

d2 =

   65

3 0
3 years ago
A long iron rod (r 5 7870 kg/m3, cp 5 447 J/kg·K, k 5 80.2 W/m·K, and a 5 23.1 3 10–6 m2/s) with diameter of 25 mm is initially
MAXImum [283]

Answer:

Time required for iron rod surface temperature to cool to 200°C is 250 seconds.

Explanation:

7 0
4 years ago
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