3 years ago

How long does it take for the Earth to make a complete revolution around the sun?

2 answers:

Alex3 years ago

8 0

365 days, 5
Earth revolves around the sun in 365 days, 5 hours, 59 minutes and 16 seconds. The time a planet takes to revolve around the sun is called a year.

timurjin [86]3 years ago

4 0

365 days so a year basically

You might be interested in

A horse pulls on a wagon. The reaction force is the wagon pulls on the horse.<br><br> true or false?

Katen [24]

Answer:

True

Explanation:

the horse pull on the wagon but friction and the wight + gravity make the wagon pull on the horse ( newton's 2ed law)

6 0

3 years ago

Read 2 more answers

Nalah labels ten rats with the numbers 1 through 10. Then, she records how long it takes each rat to run through a maze. She fin

drek231 [11]

Answer:

we have to make another question we maxed it out again lol

Explanation:

5 0

3 years ago

You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh

choli [55]

Answer:

They can be seen from a distance of 4.372 kilometers.

Explanation:

Using the Reyligh creterion for diffraction through a circular aperture we have

$\frac{x}{D}=\frac{1.22\lambda }{d}$

where symbol's have their usual meaning

thus applying values we get

$D=\frac{dx}{1.22\lambda }$

$\therefore D=\frac{0.633\times 4.61\times 10^{-3}}{1.22\times 547\times 10^{-9}}\\\\D=4372.77m\\=4.372km$

5 0

3 years ago

A person is standing on a spring bathroom scale on the floor of an elevator which is moving up and slowing down at the rate of 2

Alinara [238K]

Answer:

923.44N

Explanation:

Obviously Fn cannot equal Fg since the elevator is moving up

Where Fn is the force read on the scale

Fg is gravitational force=mg=77.6 x 9.8=760.48N

So we use this equation:

Fnet = Fn - Fg

ma = Fn - mg

77.6 x 2.1 = Fn – 760.48

162.96N = Fn – 760.48N

923.44 N = Fn

The answer is 923.44 N

6 0

3 years ago

Read 2 more answers

Ms. Stafford wants to try racing with a push start. A student pushes her at 5 m/s before the rocket kicks in. The rocket still o

Gnom [1K]

The initial velocity of Ms. Stafford is $v_0 = 5 m/s$ , while her acceleration is
$a=4 m/s^2$
This is a uniform accelerated motion, so we can calculate the total distance travelled by Ms. Stafford in a time of $t=7.0 s$ using the law of motion for a uniform accelerated motion:
$S=v_0t + \frac{1}{2} at^2 = (5 m/s)(7.0 s)+ \frac{1}{2}(2 m/s^2)(7.0 s)^2 = 84 m$

8 0

3 years ago