Answer:
18N & 360W
Explanation:
Here,
Velocity of car (v) = 72 ∗ 1000 / 60∗60 = 20m/s
weight of car = 1200N
We have,
μr = Fs / R
Fs = μr ∗ R = 0.015 ∗ 1200 = 18N
Power developed by the engine = 18 ∗ 20 =360W
<h2>Hope this helps!!!</h2>
The answer is C adding more mass(Tape) to the balls(No homo) would increase the gravitational pull.
Answer:
The magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N
Explanation:
Given;
first object with mass, m₁ = 285 kg
second object with mass, m₂ = 585 kg
distance between the two objects, r = 4.3 m
The midpoint between the two objects = r/₂ = 4.3 /2 = 2.15 m
Gravitational force between the first object and the 42 kg object;
where;
G = 6.67 x 10⁻¹¹ Nm²kg⁻²
Gravitational force between the second object and the 42 kg object
Magnitude of net gravitational force exerted on 42kg object;
F = 3.545x 10⁻⁷ N - 1.727 x 10⁻⁷ N
F = 1.818 x 10⁻⁷ N
Therefore, the magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N
A). 1,000 watts = 1 kilowatt
5,000 watts = 5 kilowatts
b). (5 kilowatts) x (2 hours) = 10 kilowatt-hours (kWh)
c). (10 kWh) x (15 cents/kWh) = $1.50