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sweet [91]
3 years ago
14

What method would produce disease resistant cattle in the shortest amount of time?

Physics
1 answer:
xenn [34]3 years ago
7 0
My brother said it is D
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a racing car traveling initially at 8.0 m/s accelerates uniformly at 10.0 m/s^2 for 5 seconds. How far does it travel in this ti
Pepsi [2]

The car travels a distance of

(8.0 m/s) (5 s) + 1/2 (10.0 m/s²) (5 s)² = 165 m

7 0
2 years ago
Particle A has charge qA and particle B has charge qB. When they are separated by a distance ri, they experience an attractive f
kumpel [21]

Answer:

r_{final}=r_{i}/4

Explanation:

We know force between 2 charges is given by

F=\frac{1}{4\pi \varepsilon }\frac{q_{1}q_{2}}{r^{2}}

It is given initial force is attractive of magnitudeF_{i}

Let r_{i} be the initial separation

Thus

F_{i}=\frac{1}{4\pi \varepsilon }\frac{q_{a}q_{b}}{r_{i}^{2}}

Now

Let r_{f} be the final separation

Thus final force becomes

\frac{1}{4\pi \varepsilon }\frac{q_{a}q_{b}}{r_{f}^{2}}

It is given F_{f} = 16F_{i}...................(i)

Using values of  F_{f} and F_{i} in equation i we have

16\times \frac{1}{4\pi \varepsilon }\frac{q_{a}q_{b}}{r_{i}^{2}} = \frac{1}{4\pi \varepsilon }\frac{q_{a}q_{b}}{r_{f}^{2}}

thus

thus\\\\(\frac{r_{i}}{r_{f}})^{2}=16\\\\\frac{r_{i}}{r_{f}}=4\\\\\therefore r_{f}=r_{i}/4

Thus the final separation is one-fourth of the initial separation

7 0
3 years ago
Find both the scalar projection compvuand the vector projection projvuof the vectoru=〈1,−1,1〉onto the vectorv=〈1,0,1〉. answer:.
forsale [732]

Its Scalar projection \sqrt{2} and Vector projection 1 (i+0j+k).

<h3>How to find scalar projection and vector projection ?</h3>

We have been given two vectors <1 -1 1> and vector <1 0 1> , we are to find out the scalar and vector projection of vector <1 -1 1> onto vector <1 0 1>

We have vector a = <1 -1 1>  and vector b = <1 0 1>

The scalar projection of vector a onto vector b means the magnitude of resolved component of vector a in the direction of vector b and is given by

The scalar projection of vector a onto vector b = \frac{vector b . vector a}{|vector b| }

                                                                             = \frac{(1-1+1)(1+0+1)}{\sqrt{1^{2} }+0+1^{2}  }

                                                                             =\frac{1^{2}  + 1^{2} }\sqrt{2}

                                                                             = \sqrt{2}

The Vector projection of vector a onto vector b means the resolved component of vector a in the direction of vector b and is given by

The vector projection of vector a onto vector b .

                                    = \frac{vector b . vector a}{| vector  b|^{2}  } (i+0j+k)

                                   = \frac{(1-1+1)(1+0+1)}{{1^{2} }+0+1^{2}  }. (i+0j+k)

                                   =  \frac{1^{2}  + 1^{2} }{\sqrt{2} } (i+0j+k)

                                   = 1 (i+0j+k).

Thus from the above conclusion we can say that scalar projection scalar projection \sqrt{2} and vector projection 1 (i+0j+k).  

Learn more about the vector projection here: brainly.com/question/17477640

#SPJ4

4 0
2 years ago
Sam threw a stone horizontally at a speed of 5m/s from a 9.8 m tall building. how much time does the stone take to hit the groun
taurus [48]
The given is a projectile motion with angle equal to 90° at which the motion would become horizontal. The projectile motion has two components for the distance. The horizontal component would progress at a constant rate each second while the vertical component would become greater as time progress. 

In this item, we are asked to determine the amount of time that would be needed for the stone to hit the ground. This can be calculated through the equation,
            
           d = V₀t + (1/2)(gt²)
It is to be noted that V₀ has a y-component equal to zero. 

Substituting this value to the equation,
          9.8 m = (0) + (1/2)(9.8 m/s²)(t²)
                  t = sqrt (2) = 1.41 s

Hence, the time would be equal to 1.41 s. 
7 0
3 years ago
Although one can electrify a glass rod by rubbing it with silk, no net charge is created.
aliya0001 [1]

Answer:True

Explanation:

When we rub a glass rod with silk cloth electrons of glass rod are stripped away by the silk cloth making glass rod Positively charged  i.e. relatively glass rod has more positive charge than negative charge.

During this Process no charge is created but transfer of the charges makes the rod relatively Positive and silk cloth relatively negative.

Thus net charge is same and no new charge is created.      

8 0
3 years ago
Read 2 more answers
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