Answer:
<h2>mass = 200.23 g</h2>
Explanation:
The density of a substance can be found by using the formula
Since we are finding the mass
<h3>mass = Density × volume</h3>
From the question
Density = 0.81 g/mL
volume = 247.2 mL
Substitute the values into the above formula and solve for the mass
mass = 0.81 × 247.2
= 200.232
We have the final answer as
<h3>mass = 200.23 g to 2 decimal places</h3>
Hope this helps you
Volcanic islands, seamounts, guyouts
Explanation:
The magma rising from this type of plate movement may produce under water volcanic activities.
The magma here would be mafic - ultramafic because it is produced from melting of oceanic plates.
As the subducting oceanic plate melts and begins to rise, it will settle and cool on the ocean floor resulting in the formation of massive and extensive seamounts.
With time, they outgrow the ocean level and forms volcanic Islands.
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Answer: The electronic configuration of nitrogen is 1s2 2s2 2p3. Thus nitrogen has a half-filled p orbital, which is comparatively more stable. Thus the p orbital is the outermost orbital. To achieve a stable gas configuration, nitrogen needs to have a fulfilled p orbital.
Explanation: please mark brainlyest i really nead it
The concentration after dilution is 1.4%.
We are aware that concentration and volume are related to each other by the formula -
= 
, where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.
Keep the values to calculate final concentration.
= (53.5 × 5.4)/205.0
Performing multiplication on Right and Side
= 288.9/205.0
Performing division on Right Hand Side
= 1.4%
Hence, the final concentration is 1.4%.
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The complete question is -
A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.
Calculate the final concentration and express your answer to two significant figures and include the appropriate units.
substitute: <span><span>t<span>1/2</span></span>=<span><span>ln(2)</span>k</span>→k=<span><span>ln(2)</span><span>t<span>1/2</span></span></span></span>
Into the appropriate equation: <span>[A<span>]t</span>=[A<span>]0</span>∗<span>e<span>−kt</span></span></span>
<span>[A<span>]t</span>=[A<span>]0</span>∗<span>e<span>−<span><span>ln(2)</span><span>t<span>1/2</span></span></span>t</span></span></span>
<span>[A<span>]t</span>=(250.0 g)∗<span>e<span>−<span><span>ln(2)</span><span>3.823 days</span></span>(7.22 days)</span></span>=67.52 g</span>
