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Nataliya [291]
3 years ago
11

Please help me on this!

Physics
1 answer:
strojnjashka [21]3 years ago
8 0

Answer:

Explanation:

Am not sure

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Since the aluminum bar is not an isolated system, the second law of thermodynamics cannot be applied to the bar alone. Rather, i
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Answer:

ΔS total ≥ 0 (ΔS total = 0 if the process is carried out reversibly in the surroundings)

Explanation:

Assuming that the entropy change in the aluminium bar is due to heat exchange with the surroundings ( the lake) , then the entropy change of the aluminium bar is, according to the second law of thermodynamics, :

ΔS al ≥ ∫dQ/T

if the heat transfer is carried out reversibly

ΔS al =∫dQ/T  

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ΔS surr ≥ -∫dQ/T = -ΔS al → ΔS surr ≥ -ΔS al = - (-1238 J/K) = 1238 J/K

the total entropy change will be

ΔS total = ΔS al + ΔS surr

ΔS total ≥ ΔS al + (-ΔS al) =

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the total entropy change will be ΔS total = 0 if the process is carried out reversibly in the surroundings

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3 years ago
How often is water added to the Earth system?
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She pulled the scarf from her neck and wiped her face.

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3. What do we call the ONLY part of the electromagnetic spectrum that we can
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Answer:

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What influences the strength of an electric field?
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Answer:

Explanation:

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