Please help me on this!

Answer in detail? Describe an activity that gives an understanding of ‘Electrostatic force’.

kvv77 [185]

Answer:

The electrostatic force is the force that exists between electrically charged particles or objects at rest.

8 0

3 years ago

atoms are unstable unless they have a similar number of protons and neutrons. To make the carbon atom stable, add 6 neutrons to

torisob [31]

Answer:

Mass number of carbon is 12.

Explanation:

Carbon atom is defined as 6 atoms in a nucleus, and the mass number is the total number of protons and neutrons in the nucleus of an atom.

Before any neutrons are added to the carbon atom, its mass number is 6; after 6 neutrons are added, the total number of protons and neutrons is now 12—the mass number becomes 12.

5 0

3 years ago

It’s estimated that there are a trillion comets in the Oort cloud, which extends out to about 50,000 AU.How much space does each

dexar [7]

Answer:

Each comet has 523 UA³
The typical spacing would be 8.05 UA
2.0181x10^21 Joules

Explanation:

Assuming comets are evenly distributed we can find first the volume of a sphere with the formula frac{{4}{3}}πr³ using 50000 as the radius, and then dividing this volume by the amount of comets. This gives a the space each comet has on average.
We apply the cube root as proposed in the question.
The kinectic energy is given K=frac{{1}{2}}mv² where m is the mass and v is the velocity. Apropriate unit are given in the question.

5 0

4 years ago

True or False One of the objections to the solar nebula theory is the angular momentum problem.

KengaRu [80]

Answer:

False, the angular momentum problem is not one of the objections to the solar nebular theory.

5 0

3 years ago

Could you please solve it with shiwing the full work

tia_tia [17]

Answer:

1.V= 640.48 m/s :total velocity in t= 5s

2. Y= 5.79m : vertical distance above the height of release (in meters) where the ball will hit a wall 13.0 m away

3. v =25m/s

4. s= (-1.5t³+26t ) m

Explanation:

1. Parabolic movement in the x-y plane , t=5s

V₀=638.6 m/s=Vx :Constant velocity in x

Vy=V₀y +gt= 0+9.8*5 = 49 m/s : variable velocity in y

$v=\sqrt{v_{x} ^{2} +v_{y} ^{2} }$

$v=\sqrt{ 638.6^{2} +49 ^{2} }$

V= 640.48 m/s : total velocity in t= 5s

2. $v_{ox} =v_{o} cos33.2=20.9*cos33,2= 17.49 m/s$

$v_{oy}=v_{o}*sin33,2 =20.9*sin33,2=11.44 m/s$

x=v₀x*t

13=v₀x*t

13=17.49*t

t=13/17.49=0.743s : time for 13.0 m away

th=v₀y/g=11.44/9.8= 1,17s :time for maximum height

at t=0.743 sthe ball is going up ,then g is negative

y=v₀y*t - 1/2 *g¨*t²

y=11.44*0.743 -1/2*9.8*0.743²

y= 5.79m : vertical distance above the height of release (in meters) where the ball will hit a wall 13.0 m away

3. s = (1t3 + -5t2 + 3) m

v=3t²-10t=3*25-50=75-50=25m/s

at t=0, s=3 m

at t=5s s=5³-5*5²+3

4. a = (-9t) m/s2

a=dv/dt=-9t

dv=-9tdt

v=∫ -9tdt

v=-9t²/2 + C1 equation (1)

in t=0 , v₀=26m/s ,in the equation (1) C1= 26

v=-9t²/2 + 26=ds/dt

ds=( -9t²/2 + 26)dt

s= ∫( -9t²/2 + 26)dt

s= -9t³/6+26t+C2 Equation 2

t = 0, s = 0 , C2=0

s= (-9t³/6+26t ) m

s= (-1.5t³+26t ) m

5 0

3 years ago