A certain chemical reaction releases 31.0 kj/g of heat for each gram of reactant consumed. How can you calculate what mass of re
1 answer:
Answer:
See explanation.
Explanation:
Hello!
In this case, since we know the heat of reaction per gram of reactant and we should know the total energy of reaction, but it is not there, we are going to assume it is 1200 J as usual in these problems, so you can change it to whatever your given heat is.
In such a way, we set up the math as shown below:
Which results:
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The block will sink
Explanation:
In general, an object with a higher density than water will sink in it, and one with a lower density will float. Now, to know if the block will float or sink, the first step is to calculate the density of the block, and to do this, the volume and mass of the block are required.
Mass of the block: 30 grames
Volume of the block:
The volume of the block is not provided, but this can be found using the dimensions given.
V (Volume) = s (side) x s x s
V = 1.5 cm x 4.8 cm x 2.3 cm
V = 16.56
Density of the block:
To find the density simply divide the mass into the volume
D (density) = M (Mass) ÷ V (Volume)
D = 30 grams ÷ 16.56
D = 1. 811 grams/
The density of the block is 1. 811 grams/
Additionally, the density of the water is 1 gram/ or 1 gram/mL. According to this, the density of the block is higher than the density of the water, and therefore this is the block sinks.
Explanation:
The given balanced reaction is as follows.
It is given that mass of ammonium nitrate is 86.0 kg.
As 1 kg = 1000 g. So, 86.0 kg = 86000 g.
Hence, moles of present will be as follows.
Moles of =
=
= 1074.42 mol
Therefore, moles of ,
and
produced by 1074.42 mole of
will be as follows.
Moles of =
= 537.21 mol
Moles of =
= 1074.42 mol
Moles of =
= 2148.84 mol
Therefore, total number of moles will be as follows.
537.21 mol + 1074.42 mol + 2148.84 mol
= 3760.47 mol
According to ideal gas equation, PV = nRT. Hence, calculate the volume as follows.
PV = nRT
1 atm \times V = 3760.47 mol \times 0.0821 L atm/mol K \times 580 K[/tex] (as = 307 + 273 = 580 K)
V = 179066.06 L
Thus, we can conclude that total volume of the gas is 179066.06 L.