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ira [324]
1 year ago
11

draw the organic product formed when 1−hexyne is treated with h2o, h2so4, and hgso4. click the draw structure button to launch t

he drawing utility.
Chemistry
1 answer:
V125BC [204]1 year ago
4 0

The organic product formed when 1−hexyne is treated with H₂O, H₂SO₄, and HgSO₄ will be 2-hexanone (structure attached).

This reaction is an example of an oxymercuration reaction of the organic product 1−hexyne.

Oxymercuration is shown in three steps to the right. The nucleophilic double bond attacks the mercury ion, releasing an acetoxy group. The mercury ion's electron pair attacks carbon on the double bond, generating a positive-charged mercuronium ion. Mercury's dxz and 6s orbitals give electrons to the double bond's lowest unoccupied molecular orbitals.

In the second stage, the nucleophilic H₂O attacks the highly modified carbon, freeing its mercury-bonding electrons. Electrons neutralize mercury ions by collapsing. Water molecules have positive-charged oxygen.

In the third stage, the negatively charged acetoxy ion released in the first step attacks the hydrogen of the water group, generating the waste product HOAc. The two electrons in the oxygen-hydrogen link collapse into oxygen, neutralizing its charge and forming alcohol.

You can also learn about organic products from the following question:

brainly.com/question/13513481

#SPJ4

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Answer:

Explanation:

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8 0
3 years ago
Please help me, thank you
Bezzdna [24]

Answer:

it's C

Explanation:

Yes

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3. How many moles of NaCl are present in 6000. La 1.5 M NaCl solution?
Leno4ka [110]

Answer:

Option A (9.0) is the correct alternative.

Explanation:

The given values are:

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= 1.5 M

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As we know,

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or,

⇒ The \ moles \ of \ NaCl=Molarity\times Volume

By putting the values, we get

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